This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A161681 #18 Nov 16 2019 15:40:46 %S A161681 2,7,11,13,19,23,47,53,61,67,71,79,83,89,107,109,127,139,151,167,191, %T A161681 193,199,223,233,239,251,271,277,293,307,359,431,433,439,463,487,499, %U A161681 503,547,557,587,593,599,631,647,673,683,719,727,769,797,859,887,919 %N A161681 Primes that are the difference between a cube and a square (conjectured values). %C A161681 The primes found among the differences are sorted in ascending order and unique primes are then extracted. I call this a "conjectured" sequence since I cannot prove that somewhere on the road to infinity there will never exist an integer pair x,y such that x^3-y^2 = 3,5,17,..., missing prime. For example, testing x^3-y^2 for x,y up to 10000, the count of some duplicates are: %C A161681 duplicate,count %C A161681 7,2 %C A161681 11,2 %C A161681 47,3 %C A161681 431,7 %C A161681 503,7 %C A161681 1999,5 %C A161681 28279,11 %C A161681 Yet for 3,5,17,29,... I did not find even one. %C A161681 [Comment from _Charles R Greathouse IV_, Nov 03 2009: 587 = 783^3 - 21910^2, 769 = 1025^3 - 32816^2, and 971 = 1295^3 - 46602^2 were skipped in the original.] %C A161681 Conjecture: The number of primes in x^3-y*2 is infinite. %C A161681 Conjecture: The number of duplicates for a given prime is finite. Then there is the other side - the primes that are not in the sequence 3, 5, 17, 29, 31, 37, 41, 43, 59, 73, 97, 101, 103, ... Looks like a lot of twin components here. Do these have an analytical form? Is there such a thing as a undecidable sequence? %C A161681 Range of A167224. - _Reinhard Zumkeller_, Oct 31 2009 %H A161681 R. Zumkeller, <a href="/a161681.txt">Some Examples</a> [From _Reinhard Zumkeller_, Oct 31 2009] %F A161681 Integers x,y such that x^3-y^2 = p where p is prime. The generation bound is 10000. %e A161681 3^3 - 4^2 = 15^3 - 58^2 = 11. %o A161681 (PARI) diffcubesq(n) = %o A161681 { %o A161681 local(a,c=0,c2=0,j,k,y); %o A161681 a=vector(floor(n^2/log(n^2))); %o A161681 for(j=1,n, %o A161681 for(k=1,n, %o A161681 y=j^3-k^2; %o A161681 if(ispseudoprime(y), %o A161681 c++; %o A161681 a[c]=y; %o A161681 ) %o A161681 ) %o A161681 ); %o A161681 a=vecsort(a); %o A161681 for(j=2,c/2, %o A161681 if(a[j]!=a[j-1], %o A161681 c2++; %o A161681 print1(a[j]","); %o A161681 if(c2>100,break); %o A161681 ) %o A161681 ); %o A161681 } %Y A161681 Cf. A000040. %K A161681 nonn %O A161681 1,1 %A A161681 _Cino Hilliard_, Jun 16 2009 %E A161681 Extended and edited by _Charles R Greathouse IV_, Nov 03 2009 %E A161681 Further edits by _N. J. A. Sloane_, Nov 09 2009