A162459 A002321*A000079.
1, 0, -4, -8, -32, -32, -128, -256, -512, -512, -2048, -4096, -12288, -16384, -16384, -32768, -131072, -262144, -786432, -1572864, -2097152, -2097152, -8388608, -16777216, -33554432, -33554432, -67108864, -134217728, -536870912, -1610612736, -4294967296
Offset: 1
Keywords
Programs
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Python
from functools import lru_cache @lru_cache(maxsize=None) def A162459(n): if n == 0: return 0 c, j = n, 2 k1 = n//j while k1 > 1: j2 = n//k1 + 1 c += (j2-j)*A162459(k1)//2**(k1-1) j, k1 = j2, n//j2 return 2**(n-1)*(j-c) # Chai Wah Wu, Mar 30 2021
Formula
a(n) = 2^(n-1)*A002321(n). - Chai Wah Wu, Mar 30 2021
Comments