cp's OEIS Frontend

A164382 Take sequence A114129, those integers that are factored into prime powers each with a distinct prime exponent. If the largest power of p dividing A114129(n) is p^q(p), p and q being primes, then a(n) = product{p|A114129(n)} q(p)^p.

%I A164382 #7 Mar 11 2014 01:32:45
%S A164382 4,9,8,32,27,25,128,72,108,2048,243,49,8192,288,125,200,131072,2187,
%T A164382 524288,1152,972,8388608,864,800,536870912,675,2147483648,18432,500,
%U A164382 1944,392,3456,177147,73728,137438953472,8748,3200,2199023255552
%N A164382 Take sequence A114129, those integers that are factored into prime powers each with a distinct prime exponent. If the largest power of p dividing A114129(n) is p^q(p), p and q being primes, then a(n) = product{p|A114129(n)} q(p)^p.
%C A164382 This is a permutation of the terms of A114129.
%e A164382 288 is factored as 2^5 * 3^2. (Since the exponents 5 and 2 are distinct primes, then 288 is in sequence A114129.) The term of this sequence that corresponds to A114129(16) = 288 is then: a(16) = 5^2 * 2^3 = 200. Notably, 200 occurs in sequence A114129, as do all other terms of this sequence.
%Y A164382 Cf. A114129.
%K A164382 nonn
%O A164382 1,1
%A A164382 _Leroy Quet_, Aug 14 2009
%E A164382 Extended by _Ray Chandler_, Mar 15 2010