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A166344 Triangle T(n, k) = coefficients of ( t(n, x) ) where t(n, x) = (1-x)^(n+1)*p(n, x)/x, p(n, x) = x*D( p(n-1, x) ), with p(1, x) = x/(1-x)^2, p(2, x) = x*(1+x)/(1-x)^3, and p(3, x) = x*(1+6*x+x^2)/(1-x)^4, read by rows.

%I A166344 #5 Mar 11 2022 21:25:18
%S A166344 1,1,1,1,6,1,1,15,15,1,1,34,90,34,1,1,73,406,406,73,1,1,152,1583,3248,
%T A166344 1583,152,1,1,311,5661,20907,20907,5661,311,1,1,630,19160,117594,
%U A166344 209070,117594,19160,630,1,1,1269,62520,604496,1750914,1750914,604496,62520,1269,1
%N A166344 Triangle T(n, k) = coefficients of ( t(n, x) ) where t(n, x) = (1-x)^(n+1)*p(n, x)/x, p(n, x) = x*D( p(n-1, x) ), with p(1, x) = x/(1-x)^2, p(2, x) = x*(1+x)/(1-x)^3, and p(3, x) = x*(1+6*x+x^2)/(1-x)^4, read by rows.
%D A166344 Douglas C. Montgomery and Lynwood A. Johnson, Forecasting and Time Series Analysis, MaGraw-Hill, New York, 1976, page 91
%H A166344 G. C. Greubel, <a href="/A166344/b166344.txt">Rows n = 1..50 of the triangle, flattened</a>
%F A166344 T(n, k) = coefficients of ( t(n, x) ) where t(n, x) = (1-x)^(n+1)*p(n, x)/x, p(n, x) = x*D( p(n-1, x) ), with p(1, x) = x/(1-x)^2, p(2, x) = x*(1+x)/(1-x)^3, and p(3, x) = x*(1+6*x+x^2)/(1-x)^4.
%F A166344 From _G. C. Greubel_, Mar 11 2022: (Start)
%F A166344 T(n, k) = t(n-1, k) - t(n-1, k-1), T(n,1) = 1, where t(n, k) = Sum_{j=0..k} (-1)^(k-j)*binomial(n+1, k-j)*b(n, j), b(n, k) = k^(n-2)*A000447(k), b(n, 0) = 1, and b(1, k) = 1.
%F A166344 T(n, n-k) = T(n, k). (End)
%e A166344 Triangle begins as:
%e A166344   1;
%e A166344   1,    1;
%e A166344   1,    6,     1;
%e A166344   1,   15,    15,      1;
%e A166344   1,   34,    90,     34,       1;
%e A166344   1,   73,   406,    406,      73,       1;
%e A166344   1,  152,  1583,   3248,    1583,     152,      1;
%e A166344   1,  311,  5661,  20907,   20907,    5661,    311,     1;
%e A166344   1,  630, 19160, 117594,  209070,  117594,  19160,   630,    1;
%e A166344   1, 1269, 62520, 604496, 1750914, 1750914, 604496, 62520, 1269, 1;
%t A166344 (* First program *)
%t A166344 p[x_, 1]:= x/(1-x)^2;
%t A166344 p[x_, 2]:= x*(1+x)/(1-x)^3;
%t A166344 p[x_, 3]:= x*(1+6*x+x^2)/(1-x)^4;
%t A166344 p[x_, n_]:= p[x, n]= x*D[p[x, n-1], x]
%t A166344 Table[CoefficientList[(1-x)^(n+1)*p[x, n]/x, x], {n,12}]//Flatten
%t A166344 (* Second program *)
%t A166344 b[n_, k_, m_]:= If[n<2, 1, If[k==0, 0, k^(n-1)*((m+3)*k^2 - m)/3]];
%t A166344 t[n_, k_, m_]:= t[n,k,m]= Sum[(-1)^(k-j)*Binomial[n+1, k-j]*b[n,j,m], {j,0,k}];
%t A166344 T[n_, k_, m_]:= T[n,k,m]= If[k==1, 1, t[n-1,k,m] - t[n-1,k-1,m]];
%t A166344 Table[T[n,k,1], {n,12}, {k,n}]//Flatten (* _G. C. Greubel_, Mar 11 2022 *)
%o A166344 (Sage)
%o A166344 def b(n,k,m):
%o A166344     if (n<2): return 1
%o A166344     elif (k==0): return 0
%o A166344     else: return k^(n-1)*((m+3)*k^2 - m)/3
%o A166344 @CachedFunction
%o A166344 def t(n,k,m): return sum( (-1)^(k-j)*binomial(n+1, k-j)*b(n,j,m) for j in (0..k) )
%o A166344 def A166344(n,k): return 1 if (k==1) else t(n-1,k,1) - t(n-1,k-1,1)
%o A166344 flatten([[A166344(n,k) for k in (1..n)] for n in (1..12)]) # _G. C. Greubel_, Mar 11 2022
%Y A166344 Cf. A166340, A166341, A166343, A166345, A166346, A166349.
%Y A166344 Cf. A000447, A123125.
%K A166344 nonn,tabl
%O A166344 1,5
%A A166344 _Roger L. Bagula_, Oct 12 2009
%E A166344 Edited by _G. C. Greubel_, Mar 11 2022