cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A171854 Number of ladders in all peakless Motzkin paths of length n (n>=0).

Original entry on oeis.org

0, 0, 0, 1, 3, 7, 19, 50, 129, 334, 862, 2220, 5715, 14706, 37836, 97353, 250535, 644905, 1660558, 4277165, 11020698, 28406449, 73245390, 188928736, 487492213, 1258305122, 3248994414, 8391747865, 21681628237, 56035444491, 144864062529
Offset: 0

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Author

Emeric Deutsch, Feb 08 2010

Keywords

Comments

A string of consecutive up steps U_1, U_2, ..., U_m and their matching down steps D_1, D_2, ..., D_m are said to form a ladder if (i) D_1, D_2, ..., D_m are consecutive steps and (ii) the sequence of pairs (U_j, D_j) (j=1,2,...,m) is maximal. For example, in the path (UU)[U]H[D]H(DD), where U=(1,1), H=(1,0), D=(1,-1), we have 2 ladders, shown between parentheses and square brackets, respectively (can be easily expressed also in RNA secondary structure terminology).

Examples

			a(5)=7 because in the eight (=A004148(5)) peakless Motzkin paths of length 5, i.e. HHHHH, HH(U)H(D), H(U)HH(D), H(U)H(D)H, (U)H(D)HH, (U)HH(D)H, (U)HHH(D) and (UU)H(DD), each path, with the exception of the first, has 1 ladder (shown between parentheses).
		

Crossrefs

Programs

  • Maple
    eq := g = 1+z*g+z^2*g*(g-1): g := RootOf(eq, g): G := z^2*(1-z^2)*g^2*(g-1)/(1-z^2*g^2): Gser := series(G, z = 0, 35): seq(coeff(Gser, z, n), n = 0 .. 32);

Formula

a(n) = Sum_{k>=0} k*A098093(n,k).
G.f. = z^2*(1-z^2)*g^2*(g-1)/(1-z^2*g^2), where g=g(z) is the g.f. of the number of peakless Motzkin paths (A004148), defined by g = 1 + z*g + z^2*g*(g-1). See also eq. (65) in the Hofacker et al. reference.
Conjecture D-finite with recurrence -(n+2)*(1390*n-8929)*a(n) +(4884*n^2-25542*n-20107)*a(n-1) +(60*n^2-6110*n-2249)*a(n-2) +(-5080*n^2+49134*n-115735)*a(n-3) +(-8476*n^2+66210*n-98877)*a(n-4) +(-3652*n^2+41338*n-109281)*a(n-5) +(2878*n-9993)*(n-7)*a(n-6)=0. - R. J. Mathar, Jul 22 2022