cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A330523 Decimal expansion of Product_{primes p} (1 - 1/p^2 - 1/p^3 + 1/p^4).

Original entry on oeis.org

5, 3, 5, 8, 9, 6, 1, 5, 3, 8, 2, 8, 3, 3, 7, 9, 9, 9, 8, 0, 8, 5, 0, 2, 6, 3, 1, 3, 1, 8, 5, 4, 5, 9, 5, 0, 6, 4, 8, 2, 2, 2, 3, 7, 4, 5, 1, 4, 1, 4, 5, 2, 7, 1, 1, 5, 1, 0, 1, 0, 8, 3, 4, 6, 1, 3, 3, 2, 8, 8, 1, 1, 9, 6, 1, 4, 5, 4, 1, 1, 0, 4, 5, 1, 1, 4, 4, 6, 5, 8, 2, 7, 3, 1, 0, 0, 2, 3, 4, 4, 0, 5, 3, 5, 1, 1
Offset: 0

Views

Author

Vaclav Kotesovec, Dec 17 2019

Keywords

Examples

			0.5358961538283379998085026313185459506482223745141452711510108346133288119...
		

Crossrefs

Programs

  • Mathematica
    Do[Print[N[Exp[-Sum[q = Expand[(p^2 + p^3 - p^4)^j]; Sum[PrimeZetaP[Exponent[q[[k]], p]] * Coefficient[q[[k]], p^Exponent[q[[k]], p]], {k, 1, Length[q]}]/j, {j, 1, t}]], 50]], {t, 10, 100, 10}]
  • PARI
    (6/Pi^2) * prodeulerrat(1 - 1/(p^2*(p+1))) \\ Amiram Eldar, Sep 08 2020

Formula

Equals (6/Pi^2) * A065465. - Amiram Eldar, Sep 08 2020

A183030 Decimal expansion of Sum_{j>=1} tau(j)/j^3 = zeta(3)^2.

Original entry on oeis.org

1, 4, 4, 4, 9, 4, 0, 7, 9, 8, 4, 3, 3, 6, 3, 4, 2, 3, 3, 9, 1, 3, 6, 8, 5, 0, 7, 8, 8, 0, 6, 9, 8, 7, 8, 2, 7, 1, 8, 3, 7, 3, 5, 4, 0, 5, 7, 6, 3, 8, 8, 8, 6, 7, 4, 1, 3, 1, 4, 3, 4, 1, 6, 1, 8, 9, 8, 5, 8, 3, 8, 5, 6, 1, 3, 1, 3, 5, 4, 1, 0, 1, 9, 6, 6, 1, 9
Offset: 1

Views

Author

R. J. Mathar, Dec 18 2010

Keywords

Comments

This is the zeta-function Sum_{j>=1} A000005(j)/j^s evaluated at s=3. At s=2 we find A098198, at s=4 A183031.
Since tau(n)/n^3 is a multiplicative function, one finds an Euler product for the sum, which is expanded with an Euler transformation to a product of Riemann zeta functions as in A175639 for numerical evaluation.

Examples

			1.4449407984336342339136.. = 1 +2/2^3 +2/3^3 +3/4^3 +2/5^3 +4/6^3 +2/7^3+...
		

Crossrefs

Programs

Formula

Equals the Euler product Product_{p= A000040} (1+ (2*p^s-1)/(p^s-1)^2) at s=3, or the square of A002117.

A183031 Decimal expansion of Sum_{j>=1} tau(j)/j^4 = Pi^8/8100.

Original entry on oeis.org

1, 1, 7, 1, 4, 2, 3, 5, 8, 2, 2, 3, 0, 9, 3, 5, 0, 6, 2, 6, 0, 8, 4, 6, 6, 1, 1, 1, 5, 9, 3, 4, 2, 7, 8, 7, 6, 1, 3, 5, 4, 5, 4, 2, 5, 5, 7, 5, 8, 1, 5, 8, 3, 5, 7, 0, 5, 0, 6, 2, 8, 5, 6, 9, 7, 6, 1, 3, 4, 6, 7, 7, 8, 0, 0, 3, 8, 7, 3, 6, 1, 6, 7, 9, 4
Offset: 1

Views

Author

R. J. Mathar, Dec 18 2010

Keywords

Comments

This is the zeta-function Sum_{j>=1} A000005(j)/j^s evaluated at s=4. At s=2, we find A098198; at s=3, A183030.
Since tau(n)/n^4 is a multiplicative function, one finds an Euler product for the sum, which is expanded with an Euler transformation to a product of Riemann zeta functions as in A175639 for numerical evaluation.

Examples

			1.1714235822309350626084... = 1 + 2/2^4 + 2/3^4 + 3/4^4 + 2/5^4 + 4/6^4 + 2/7^4 + ...
		

Crossrefs

Programs

Formula

Equals the Euler product Product_{p prime} (1 + (2*p^s - 1)/(p^s - 1)^2) at s=4, which is the square of A013662.
Showing 1-3 of 3 results.