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A178517 Triangle read by rows: T(n,k) is the number of non-derangement permutations of {1,2,...,n} having genus k (see first comment for definition of genus).

%I A178517 #8 Nov 01 2012 12:36:52
%S A178517 1,1,0,4,0,0,11,4,0,0,36,40,0,0,0,117,290,48,0,0,0,393,1785,1008,0,0,
%T A178517 0,0,1339,9996,12712,1440,0,0,0,0,4630,52584,123858,48312,0,0,0,0,0,
%U A178517 16193,264720,1027446,904840,80640,0,0,0,0,0,57201,1290135,7627158,12449800,3807936,0
%N A178517 Triangle read by rows: T(n,k) is the number of non-derangement permutations of {1,2,...,n} having genus k (see first comment for definition of genus).
%C A178517 The genus g(p) of a permutation p of {1,2,...,n} is defined by g(p)=(1/2)[n+1-z(p)-z(cp')], where p' is the inverse permutation of p, c = 234...n1 = (1,2,...,n), and z(q) is the number of cycles of the permutation q.
%C A178517 The sum of the entries in row n is A002467(n).
%C A178517 The number of entries in row n is floor(n/2).
%C A178517 T(n,0) = A106640(n-1) .
%D A178517 S. Dulucq and R. Simion, Combinatorial statistics on alternating permutations, J. Algebraic Combinatorics, 8 (1998), 169-191.
%e A178517 T(3,0)=4 because all non-derangements of {1,2,3}, namely 123=(1)(2)(3), 132=(1)(23), 213=(12)(3), and 321=(13)(2) have genus 0. This follows easily from the fact that a permutation p of {1,2,...,n} has genus 0 if and only if the cycle decomposition of p gives a noncrossing partition of {1,2,...,n} and each cycle of p is increasing (see Lemma 2.1 of the Dulucq-Simion reference).
%e A178517 Triangle starts:
%e A178517 [ 1]  1,
%e A178517 [ 2]  1, 0,
%e A178517 [ 3]  4, 0, 0,
%e A178517 [ 4]  11, 4, 0, 0,
%e A178517 [ 5]  36, 40, 0, 0, 0,
%e A178517 [ 6]  117, 290, 48, 0, 0, 0,
%e A178517 [ 7]  393, 1785, 1008, 0, 0, 0, 0,
%e A178517 [ 8]  1339, 9996, 12712, 1440, 0, 0, 0, 0,
%e A178517 [ 9]  4630, 52584, 123858, 48312, 0, 0, 0, 0, 0,
%e A178517 [10]  16193, 264720, 1027446, 904840, 80640, 0, 0, 0, 0, 0,
%e A178517 [11]  57201, 1290135, 7627158, 12449800, 3807936, 0, 0, 0, 0, 0, 0,
%e A178517 [12]  203799, 6133930, 52188774, 140356480, 96646176, 7257600, 0, ...,
%e A178517 [13]  731602, 28603718, 335517468, 1373691176, 1749377344, 448306560, 0, ...,
%e A178517 ...
%p A178517 n := 7: with(combinat): P := permute(n): inv := proc (p) local j, q: for j to nops(p) do q[p[j]] := j end do: [seq(q[i], i = 1 .. nops(p))] end proc: nrfp := proc (p) local ct, j: ct := 0: for j to nops(p) do if p[j] = j then ct := ct+1 else end if end do: ct end proc: nrcyc := proc (p) local pc: pc := convert(p, disjcyc): nops(pc)+nrfp(p) end proc: b := proc (p) local c: c := [seq(i+1, i = 1 .. nops(p)-1), 1]: [seq(c[p[j]], j = 1 .. nops(p))] end proc: gen := proc (p) options operator, arrow: (1/2)*nops(p)+1/2-(1/2)*nrcyc(p)-(1/2)*nrcyc(b(inv(p))) end proc: NDER := {}: for i to factorial(n) do if nrfp(P[i]) > 0 then NDER := `union`(NDER, {P[i]}) else end if end do: f[n] := sort(add(t^gen(NDER[j]), j = 1 .. nops(NDER))): seq(coeff(f[n], t, j), j = 0 .. floor((1/2)*n)-1); # yields the entries in the specified row n
%Y A178517 Cf. A177267 (genus of all permutations).
%Y A178517 Cf. A178514 (genus of derangements), A178515 (genus of involutions), A178516 (genus of up-down permutations), A178518 (permutations of [n] having genus 0 and p(1)=k), A185209 (genus of connected permutations).
%Y A178517 Cf. A002467, A106640.
%K A178517 nonn,hard,tabl
%O A178517 1,4
%A A178517 _Emeric Deutsch_, May 30 2010
%E A178517 Terms beyond row 7 from _Joerg Arndt_, Nov 01 2012.