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A178982 Partial sums of floor(Fibonacci(n)/2).

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%I A178982 #30 Jul 04 2019 03:39:04
%S A178982 0,0,0,1,2,4,8,14,24,41,68,112,184,300,488,793,1286,2084,3376,5466,
%T A178982 8848,14321,23176,37504,60688,98200,158896,257105,416010,673124,
%U A178982 1089144,1762278,2851432,4613721,7465164,12078896,19544072,31622980
%N A178982 Partial sums of floor(Fibonacci(n)/2).
%C A178982 Partial sums of A004695.
%H A178982 Mircea Merca, <a href="http://www.cs.uwaterloo.ca/journals/JIS/VOL14/Merca/merca3.html">Inequalities and Identities Involving Sums of Integer Functions</a> J. Integer Sequences, Vol. 14 (2011), Article 11.9.1.
%F A178982 a(n) = round(Fibonacci(n+2)/2 - (n+2)/3).
%F A178982 a(n) = round(Fibonacci(n+2)/2 - n/3 - 1/2).
%F A178982 a(n) = floor(Fibonacci(n+2)/2 - n/3 - 1/2).
%F A178982 a(n) = ceiling(Fibonacci(n+2)/2 - (n+1)/3 - 1/2).
%F A178982 a(n) = a(n-3) + Fibonacci(n) - 1, n > 3.
%F A178982 a(n) = 2*a(n-1) - 2*a(n-4) + a(n-6), n > 5.
%F A178982 G.f.: -x^3 / ( (x^2+x+1)*(x^2+x-1)*(x-1)^2 ).
%F A178982 a(n) = (1/2) * (Fibonacci(n+2) + floor(n/3) - n - 1). - _Ralf Stephan_, Jan 19 2014
%e A178982 a(4) = 0 + 0 + 0 + 1 + 1 = 2.
%p A178982 seq(round(fibonacci(n+2)/2-(n+2)/3),n=0..40).
%t A178982 f[n_] := Floor[Fibonacci@n/2]; Accumulate@ Array[f, 38, 0]
%Y A178982 Cf. A004695, A164397.
%K A178982 nonn
%O A178982 0,5
%A A178982 _Mircea Merca_, Jan 02 2011