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A180258 a(n) = 2^(q*r) mod p for the n-th odd number with exactly 3 distinct prime factors p < q < r.

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%I A180258 #18 Jun 27 2024 22:15:53
%S A180258 2,2,2,2,2,2,2,2,2,2,2,2,2,3,2,2,2,2,3,2,2,2,2,2,2,2,2,3,2,2,2,2,2,2,
%T A180258 2,2,2,2,3,2,2,2,4,2,3,2,2,2,2,2,2,2,2,2,2,2,2,3,2,2,2,2,3,2,2,2,2,2,
%U A180258 2,3,2,2,4,2,2,3,2,2,2,2,4,2,2,3,2,2,3,2,2,2,2,2,2,2,2,2,2,2,2,2
%N A180258 a(n) = 2^(q*r) mod p for the n-th odd number with exactly 3 distinct prime factors p < q < r.
%H A180258 Charles R Greathouse IV, <a href="/A180258/b180258.txt">Table of n, a(n) for n = 1..10000</a>
%e A180258 a(1) = 2^(5*7) mod 3 = 2, because A046389(1) = 105 = 3*5*7 and 3 < 5 < 7.
%Y A180258 Cf. A046389, A180197, A180257.
%K A180258 nonn
%O A180258 1,1
%A A180258 _Juri-Stepan Gerasimov_, Jan 17 2011
%E A180258 More terms and corrected a(28) from _Nathaniel Johnston_, Jan 18 2011