cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A181371 Triangle read by rows: T(n,k) is the number of ternary words (i.e., finite sequences of 0's, 1's and 2's) of length n having k occurrences of 01's (0 <= k <= floor(n/2)).

Original entry on oeis.org

1, 3, 8, 1, 21, 6, 55, 25, 1, 144, 90, 9, 377, 300, 51, 1, 987, 954, 234, 12, 2584, 2939, 951, 86, 1, 6765, 8850, 3573, 480, 15, 17711, 26195, 12707, 2305, 130, 1, 46368, 76500, 43398, 10008, 855, 18, 121393, 221016, 143682, 40426, 4740, 183, 1, 317811
Offset: 0

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Author

Emeric Deutsch, Oct 31 2010

Keywords

Comments

Row n contains 1 + floor(n/2) entries.
Sum of entries in row n is 3^n = A000244(n).
T(n,0) = F(2n+2) = A001906(n+1) (even-subscripted Fibonacci numbers).
T(n,1) = A001871(n-2).
Sum_{k>=0}k*T(n,k) = (n-1)*3^(n-2) = A027471(n) (n>=1).

Examples

			T(3,1)=6 because we have 010, 011, 012, 001, 101 and 201.
T(4,2)=1 because we have 0101.
Triangle starts:
    1;
    3;
    8,  1;
   21,  6;
   55, 25,  1;
  144, 90,  9;
		

Crossrefs

Programs

  • Maple
    G := 1/(1-3*z+z^2-t*z^2): Gser := simplify(series(G, z = 0, 15)): for n from 0 to 13 do P[n] := sort(coeff(Gser, z, n)) end do: for n from 0 to 13 do seq(coeff(P[n], t, k), k = 0 .. floor((1/2)*n)) end do; # yields sequence in triangular form

Formula

G.f. = G(t,z) = 1/(1 - 3z + z^2 - tz^2).