A182298 Smallest complementary perimeter, as defined in the comments, among all sets of nonnegative integers whose volume (sum) is n.
0, 2, 4, 3, 6, 5, 4, 7, 7, 6, 5, 10, 8, 8, 7, 6, 12, 11, 9, 9, 8, 7, 11, 13, 12, 10, 10, 9, 8, 15, 12, 14, 13, 11, 11, 10, 9, 17, 16, 13, 15, 14, 12, 12, 11, 10, 17, 18, 17, 14, 16, 15, 13, 13, 12, 11, 16, 18, 19, 18, 15, 17, 16, 14, 14, 13, 12, 21, 17, 19, 20
Offset: 0
Keywords
Examples
For n=8, the set S={0,1,3,4} has volume (total sum) 8 and complementary perimeter (the sum of 2 and 5) is 7. No other set of volume 8 has a smaller complementary perimeter, so a(8)=7. Similarly, for n=11, the set S={2,4,5} has volume 11=2+4+5 and complementary perimeter 10=1+3+6. This is the smallest among all sets with volume 11, so a(11)=10.
Links
- Martin Ehrenstein, Table of n, a(n) for n = 0..250
- Patrick Devlin, Sets with High Volume and Low Perimeter, arXiv:1107.2954 [math.CO], 2011.
- Patrick Devlin, Integer Subsets with High Volume and Low Perimeter, arXiv:1202.1331 [math.CO], 2012.
- Patrick Devlin, Integer Subsets with High Volume and Low Perimeter, INTEGERS, Vol. 12, #A32.
- J. Miller, F. Morgan, E. Newkirk, L. Pedersen and D. Seferis, Isoperimetric Sets of Integers, Math. Mag. 84 (2011) 37-42.
Crossrefs
Cf. A186053.
Formula
Following the notation in the link, for n >= 0, write n = (0+1+2+...+f(n)) - g(n), be the representation of n with f(n) and g(n) minimal such that 0 <= g(n) <= f(n). Then f(n) = A002024(n) = round(sqrt(2n)), and g(n) = A025581(n) = f(n)*(f(n)+1)/2 - n.
Finally, let Q(n):=a(n), and let P(n):=A186053(n). Then unless n is one of the 177 known counterexamples tabulated in the link, we have P(n) = f(n) + Q(g(n)), and Q(n) = 1 + f(n) + P(g(n)).
Extensions
More terms from Martin Ehrenstein, Nov 16 2023
Comments