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A182495 Number of letters in Turkish words for months of year.

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%I A182495 #30 Sep 01 2025 23:43:36
%S A182495 4,5,4,5,5,7,6,7,5,4,5,6,4,5,4,5,5,7,6,7,5,4,5,6,4,5,4,5,5,7,6,7,5,4,
%T A182495 5,6,4,5,4,5,5,7,6,7,5,4,5,6,4,5,4,5,5,7,6,7,5,4,5,6,4,5,4,5,5,7,6,7,
%U A182495 5,4,5,6,4,5,4,5,5,7,6,7,5,4,5,6,4,5,4
%N A182495 Number of letters in Turkish words for months of year.
%C A182495 Period 12: repeat [4, 5, 4, 5, 5, 7, 6, 7, 5, 4, 5, 6].
%C A182495 In Turkish, the months are "Ocak", "Subat", "Mart", "Nisan", "Mayis", "Haziran", "Temmuz", "Agustos", "Eylul", "Ekim", "Kasim", "Aralik" beginning from January.
%H A182495 Wikipedia, <a href="https://en.wikipedia.org/wiki/Turkish_months">Turkish months</a>.
%H A182495 <a href="/index/Ca#calendar">Index entries for sequences related to calendars</a>.
%H A182495 <a href="/index/Periodic#12">Index to 12-periodic sequences</a>.
%H A182495 <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,0,0,1).
%F A182495 From _Elmo R. Oliveira_, Jul 20 2024: (Start)
%F A182495 G.f.: x*(4 + 5*x + 4*x^2 + 5*x^3 + 5*x^4 + 7*x^5 + 6*x^6 + 7*x^7 + 5*x^8 + 4*x^9 + 5*x^10 + 6*x^11)/(1 - x^12).
%F A182495 a(n) = a(n-12) for n > 12. (End)
%e A182495 a(1) = 4 since January in Turkish is "Ocak" which has four letters.
%Y A182495 Cf. A031139, A103742, A161376.
%K A182495 nonn,word,easy,changed
%O A182495 1,1
%A A182495 _Hasan Yurtoglu_, May 02 2012