A182577 Number of ones in Zeckendorf representation of n!
1, 1, 1, 2, 2, 4, 3, 5, 6, 9, 8, 11, 11, 11, 16, 17, 17, 18, 23, 23, 28, 31, 33, 27, 33, 29, 40, 37, 42, 42, 41, 44, 47, 44, 53, 56, 57, 50, 64, 55, 59, 68, 63, 72, 70, 61, 69, 85, 80, 83, 87, 97, 98, 101, 87, 91, 100, 102, 114, 108, 116, 109, 117, 117, 113, 124
Offset: 0
Keywords
Examples
5! = {1, 0, 0, 1, 0, 1, 0, 0, 1, 0} in the Zeckendorf base.
Links
- Chai Wah Wu, Table of n, a(n) for n = 0..10000
Programs
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Python
from math import factorial def A182577(n): m, tlist, s = factorial(n), [1,2], 0 while tlist[-1]+tlist[-2] <= m: tlist.append(tlist[-1]+tlist[-2]) for d in tlist[::-1]: if d <= m: s += 1 m -= d return s # Chai Wah Wu, Jun 15 2018