A186342 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f and g are the pentagonal numbers and the octagonal numbers. Complement of A186343.
1, 3, 5, 7, 8, 10, 12, 13, 15, 17, 18, 20, 22, 24, 25, 27, 29, 30, 32, 34, 36, 37, 39, 41, 42, 44, 46, 48, 49, 51, 53, 54, 56, 58, 59, 61, 63, 65, 66, 68, 70, 71, 73, 75, 77, 78, 80, 82, 83, 85, 87, 88, 90, 92, 94, 95, 97, 99, 100, 102, 104, 106, 107, 109, 111, 112, 114, 116, 118, 119, 121, 123, 124, 126, 128, 129, 131, 133, 135, 136, 138, 140, 141, 143, 145, 147, 148, 150, 152, 153, 155, 157, 158, 160, 162, 164, 165, 167, 169, 170
Offset: 1
Keywords
Examples
First, write 1..5...12....22..35..... (pentagonal) 1....8....21........40.. (octagonal) Then replace each number by its rank, where ties are settled by ranking the pentagonal number before the octagonal: a=(1,3,5,7,8,10,12,13,15,...)=A186342 b=(2,4,6,9,11,14,16,19,21,...)=A186343.
Programs
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Mathematica
(* adjusted joint ranking; general formula *) d=1/2; u=3/2; v=-1/2; w=0; x=3; y=-2; z=0; h[n_]:=-y+(4x(u*n^2+v*n+w-z-d)+y^2)^(1/2); a[n_]:=n+Floor[h[n]/(2x)]; k[n_]:=-v+(4u(x*n^2+y*n+z-w+d)+v^2)^(1/2); b[n_]:=n+Floor[k[n]/(2u)]; Table[a[n], {n, 1, 100}] (* A186342 *) Table[b[n], {n, 1, 100}] (* A186343 *)
Comments