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A186542 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-2+3j^2. Complement of A186541.

%I A186542 #7 Oct 12 2022 15:21:47
%S A186542 1,5,7,10,13,16,19,21,24,27,29,32,35,38,40,43,46,49,51,54,57,60,62,65,
%T A186542 68,71,73,76,79,81,84,87,90,92,95,98,101,103,106,109,111,114,117,120,
%U A186542 122,125,128,131,133,136,139,142,144,147,150,152,155,158,161,163,166,169,172,174,177,180,183,185,188,191,193,196,199,202,204,207,210,213,215,218,221,224,226,229,232,234,237,240
%N A186542 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-2+3j^2.  Complement of A186541.
%C A186542 See A186219 for a discussion of adjusted joint rank sequences.
%H A186542 Sean A. Irvine, <a href="/A186542/b186542.txt">Table of n, a(n) for n = 1..10000</a>
%F A186542 a(n)=n+floor(sqrt((1/3)n^2+5/6))=A186541(n).
%F A186542 b(n)=n+floor(sqrt(3n^2-5/2))=A186542(n).
%e A186542 First, write
%e A186542 1..4..9..16..25..36..49..... (i^2)
%e A186542 .........10.....25.....46.. (-2+3j^2)
%e A186542 Then replace each number by its rank, where ties are settled by ranking i^2 after -2+3j^2:
%e A186542 a=(2,3,4,6,8,9,11,12,14,15,17,18,..)=A186541
%e A186542 b=(1,5,7,10,13,16,19,21,24,27,29...)=A186542.
%t A186542 (See A186541.)
%Y A186542 Cf. A186219, A186539, A186540, A186541.
%K A186542 nonn
%O A186542 1,2
%A A186542 _Clark Kimberling_, Feb 23 2011