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A187478 Rank transform of the sequence floor(3(n-2)/2); complement of A187479.

%I A187478 #8 Dec 26 2023 10:11:49
%S A187478 1,2,3,6,8,9,11,13,15,17,18,20,22,24,26,28,29,31,33,35,36,39,40,42,44,
%T A187478 46,48,49,51,53,55,57,58,60,62,64,66,68,69,71,73,75,77,79,80,82,84,86,
%U A187478 88,90,91,93,95,97,98,101,102,104,106,108,109,111,113,115,117,119,120
%N A187478 Rank transform of the sequence floor(3(n-2)/2); complement of A187479.
%C A187478 See A187224.  Although the first term of floor(3(n-2)/2) is negative, we can replace it by 0 without affecting the same joint rankings; thus, the procedure described at A187224 applies.
%t A187478 seqA = Table[Floor[3(n-2)/2], {n, 1, 180}]
%t A187478   seqB = Table[n, {n, 1, 80}];        (* A000027 *)
%t A187478 jointRank[{seqA_, seqB_}] := {Flatten@Position[#1, {_, 1}],
%t A187478 Flatten@Position[#1, {_, 2}]} &[Sort@Flatten[{{#1, 1} & /@ seqA,
%t A187478 {#1, 2} & /@ seqB}, 1]];
%t A187478 limseqU = FixedPoint[jointRank[{seqA, #1[[1]]}] &, jointRank[{seqA, seqB}]][[1]]                                     (* A187478 *)
%t A187478 Complement[Range[Length[seqA]], limseqU]  (* A187479 *)
%t A187478 (* by _Peter J. C. Moses_, Mar 10 2011 *)
%Y A187478 Cf. A187422, A187476, A187479.
%K A187478 nonn
%O A187478 1,2
%A A187478 _Clark Kimberling_, Mar 10 2011