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A187574 Rank transform of the sequence floor(n*3^(1/3)); complement of A187575.

%I A187574 #15 Jul 23 2024 08:40:27
%S A187574 1,3,5,6,9,10,12,14,15,17,19,21,23,25,26,28,30,31,34,35,37,39,41,42,
%T A187574 45,46,48,50,51,54,55,57,59,61,62,64,66,67,70,71,73,75,77,79,80,82,84,
%U A187574 86,87,90,91,93,95,96,98,100,102,104,106,107,109,111,112,115,116,118,120,122,124,125,127,129,131,132,135,136,138,140,142,143,145,147,149,151,152,154,156,158,160
%N A187574 Rank transform of the sequence floor(n*3^(1/3)); complement of A187575.
%C A187574 See A187224.
%t A187574 seqA = Table[Floor[n*3^(1/3)], {n, 1, 220}] (*A059539*)
%t A187574 seqB = Table[n, {n, 1, 220}];(*A000027*)
%t A187574 jointRank[{seqA_,
%t A187574    seqB_}] := {Flatten@Position[#1, {_, 1}],
%t A187574     Flatten@Position[#1, {_, 2}]} &[
%t A187574   Sort@Flatten[{{#1, 1} & /@ seqA, {#1, 2} & /@ seqB}, 1]];
%t A187574 limseqU =
%t A187574 FixedPoint[jointRank[{seqA, #1[[1]]}] &,
%t A187574    jointRank[{seqA, seqB}]][[1]] (*A187574*)
%t A187574 Complement[Range[Length[seqA]], limseqU]  (*A187575*)
%t A187574 (* _Peter J. C. Moses_, Mar 11 2011 *)
%Y A187574 Cf. A187224, A187575, A059539.
%K A187574 nonn
%O A187574 1,2
%A A187574 _Clark Kimberling_, Mar 11 2011