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A187683 Rank transform of the sequence floor(2n/3); complement of A187683.

%I A187683 #5 Dec 04 2016 19:46:24
%S A187683 1,2,4,5,7,8,9,11,13,14,15,17,18,20,22,23,24,26,27,28,30,31,33,35,36,
%T A187683 37,39,40,42,43,44,46,47,48,50,52,53,55,56,57,59,61,62,64,65,66,68,70,
%U A187683 71,72,74,75,76,78,79,81,83,84,85,87,88,90,91,92,94,96,97,99,100,101,103,105,106,108,109,110,112,113,114,116,118,119,120,122,123,125,127,128,129,131,132,133,135,136,138
%N A187683 Rank transform of the sequence floor(2n/3); complement of A187683.
%C A187683 See A187224.
%t A187683 seqA = Table[Floor[2n/3], {n, 1, 220}]
%t A187683 seqB = Table[n, {n, 1, 220}];(*A000027*)
%t A187683 jointRank[{seqA_,
%t A187683    seqB_}] := {Flatten@Position[#1, {_, 1}],
%t A187683     Flatten@Position[#1, {_, 2}]} &[
%t A187683   Sort@Flatten[{{#1, 1} & /@ seqA, {#1, 2} & /@ seqB}, 1]];
%t A187683 limseqU =
%t A187683  FixedPoint[jointRank[{seqA, #1[[1]]}] &,
%t A187683    jointRank[{seqA, seqB}]][[1]] (*A187683*)
%t A187683 Complement[Range[Length[seqA]], limseqU]  (*A187684*)
%t A187683 (*by _Peter J. C. Moses_, Mar 12 2011*)
%Y A187683 Cf. A187224, A187684.
%K A187683 nonn
%O A187683 1,2
%A A187683 _Clark Kimberling_, Mar 12 2011