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A193419 Numbers n such that 4n+3 is a palindromic prime.

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%I A193419 #16 Nov 21 2013 12:50:19
%S A193419 0,1,2,32,37,47,95,181,196,229,2827,2852,3332,3457,3482,3862,3887,
%T A193419 4367,4492,4847,4972,4997,7525,7550,7600,7675,7700,8080,8105,8635,
%U A193419 8710,9065,9140,9520,9545,9695,17551,17626,17651,18056,18181,18511,18686,19091,19166
%N A193419 Numbers n such that 4n+3 is a palindromic prime.
%C A193419 The subsequence of primes p such that 4p+3 is a palindromic prime begins: 2, 37, 47, 181, 229, 3457.
%F A193419 {n such that A004767(n) is in A002385}.
%e A193419 a(1) = 2 because 4*2 + 3 = 11, and R(11) = 11 is prime.
%e A193419 a(2) = 37 because 4*37 + 3 = 151 is prime, and R(151) = 151.
%t A193419 ppQ[n_]:=Module[{c=4n+3,d},d=IntegerDigits[c];PrimeQ[c]&&d == Reverse[ d]]; Select[Range[0,20000],ppQ] (* _Harvey P. Dale_, Aug 02 2011 *)
%Y A193419 Cf. A000040, A002385, A004767, A004086, A192261.
%K A193419 nonn,easy,base
%O A193419 1,3
%A A193419 _Jonathan Vos Post_, Jul 26 2011