A194293 Triangular array: g(n,k)=number of fractional parts (i*r) in interval [(k-1)/n, k/n], for 1<=i<=n, 1<=k<=n, r=(1+sqrt(5))/2, the golden ratio.
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 2, 0, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 2, 1, 1, 1, 1, 0, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
Offset: 1
Examples
First ten rows: 1 1..1 1..1..1 1..1..1..1 1..1..1..1..1 1..1..1..1..1..1 1..1..1..1..2..1..0 1..1..1..1..1..1..1..1 1..0..2..0..1..2..1..1..1 1..1..1..1..1..1..1..1..1..1
Crossrefs
Cf. A194293.
Programs
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Mathematica
r = GoldenRatio; f[n_, k_, i_] := If[(k - 1)/n <= FractionalPart[i*r] < k/n, 1, 0] g[n_, k_] := Sum[f[n, k, i], {i, 1, n}] TableForm[Table[g[n, k], {n, 1, 14}, {k, 1, n}]] Flatten[%] (* A194293 *)
Comments