A195152 Square array read by antidiagonals with T(n,k) = n*((k+2)*n-k)/2, n=0, +- 1, +- 2,..., k>=0.
0, 1, 0, 1, 1, 0, 4, 2, 1, 0, 4, 5, 3, 1, 0, 9, 7, 6, 4, 1, 0, 9, 12, 10, 7, 5, 1, 0, 16, 15, 15, 13, 8, 6, 1, 0, 16, 22, 21, 18, 16, 9, 7, 1, 0, 25, 26, 28, 27, 21, 19, 10, 8, 1, 0, 25, 35, 36, 34, 33, 24, 22, 11, 9, 1, 0, 36, 40, 45, 46, 40, 39, 27, 25, 12, 10, 1, 0
Offset: 0
Examples
Array begins: . 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,... . 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,... . 1, 2, 3, 4, 5, 6, 7, 8, 9, 10,... . 4, 5, 6, 7, 8, 9, 10, 11, 12, 13,... . 4, 7, 10, 13, 16, 19, 22, 25, 28, 31,... . 9, 12, 15, 18, 21, 24, 27, 30, 33, 36,... . 9, 15, 21, 27, 33, 39, 45, 51, 57, 63,... . 16, 22, 28, 34, 40, 46, 52, 58, 64, 70,... . 16, 26, 36, 46, 56, 66, 76, 86, 96, 106,... . 25, 35, 45, 55, 65, 75, 85, 95, 105, 115,... . 25, 40, 55, 70, 85, 100, 115, 130, 145, 160,... ...
Crossrefs
Formula
T(n,k) = (k+2)*n*(n+1)/8+(k-2)*((2*n+1)*(-1)^n-1)/16, n >= 0 and k >= 0. - Omar E. Pol, Oct 01 2011
Comments