cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A197145 Decimal expansion of the shortest distance from the x axis through (3,1) to the line y=2x.

This page as a plain text file.
%I A197145 #6 Mar 30 2012 18:57:52
%S A197145 3,7,4,2,3,8,9,1,4,2,4,4,5,1,8,4,1,9,5,1,8,5,8,7,4,1,5,7,1,6,1,4,0,6,
%T A197145 6,7,0,4,5,0,6,4,6,4,8,5,2,6,0,5,4,6,0,6,9,0,4,8,1,7,1,5,0,7,3,7,4,9,
%U A197145 5,6,2,2,6,8,0,8,9,9,8,5,9,9,2,0,1,0,6,0,7,8,9,0,7,6,1,6,9,9,6
%N A197145 Decimal expansion of the shortest distance from the x axis through (3,1) to the line y=2x.
%C A197145 The shortest segment from one side of an angle T through a point P inside T is called the Philo line of P in T.  For discussions and guides to related sequences, see A197032, A197008 and A195284.
%e A197145 length of Philo line:    3.7423891424451...
%e A197145 endpoint on x axis:    (3.82891, 0); see A197144
%e A197145 endpoint on line y=2x: (1.44062, 2.88124)
%t A197145 f[t_] := (t - k*t/(k + m*t - m*h))^2 + (m*k*t/(k + m*t - m*h))^2;
%t A197145 g[t_] := D[f[t], t]; Factor[g[t]]
%t A197145 p[t_] :=  h^2 k + k^3 - h^3 m - h k^2 m - 3 h k t + 3 h^2 m t + 2 k t^2 - 3 h m t^2 + m t^3
%t A197145 m = 2; h = 3; k = 1;(* slope m, point (h,k) *)
%t A197145 t = t1 /. FindRoot[p[t1] == 0, {t1, 1, 2}, WorkingPrecision -> 100]
%t A197145 RealDigits[t]  (* A197144 *)
%t A197145 {N[t], 0} (* endpoint on x axis *)
%t A197145 {N[k*t/(k + m*t - m*h)],
%t A197145 N[m*k*t/(k + m*t - m*h)]} (* endpt on line y=2x *)
%t A197145 d = N[Sqrt[f[t]], 100]
%t A197145 RealDigits[d]  (* A197145 *)
%t A197145 Show[Plot[{k*(x - t)/(h - t), m*x}, {x, 0, 4}],
%t A197145 ContourPlot[(x - h)^2 + (y - k)^2 == .002, {x, 0, 4}, {y, 0, 3}], PlotRange -> {0, 3}, AspectRatio -> Automatic]
%Y A197145 Cf. A197032, A197144, A197008, A195284.
%K A197145 nonn,cons
%O A197145 1,1
%A A197145 _Clark Kimberling_, Oct 11 2011