A202333 Number of (n+1) X 7 binary arrays with consecutive windows of two bits considered as a binary number nondecreasing in every row and column.
81, 270, 746, 1796, 3896, 7790, 14588, 25885, 43903, 71658, 113154, 173606, 259694, 379850, 544580, 766823, 1062349, 1450198, 1953162, 2598312, 3417572, 4448342, 5734172, 7325489, 9280379, 11665426, 14556610, 18040266, 22214106, 27188306
Offset: 1
Keywords
Examples
Some solutions for n=5: ..0..0..0..0..0..1..1....0..0..0..0..0..1..0....0..0..0..0..0..0..0 ..0..0..0..0..1..1..1....0..0..0..0..1..1..1....0..0..0..0..0..0..0 ..0..0..0..0..1..1..1....0..0..1..1..1..1..1....0..0..0..0..0..0..1 ..0..0..0..0..1..1..1....0..0..1..1..1..1..1....0..0..0..0..0..0..1 ..0..0..0..1..1..1..1....1..1..1..1..1..1..1....0..0..0..0..0..1..1 ..0..0..0..0..1..1..1....0..1..1..1..1..1..1....0..0..0..1..1..1..1
Links
- R. H. Hardin, Table of n, a(n) for n = 1..210
Crossrefs
Cf. A202335.
Formula
Empirical: a(n) = (1/2520)*n^7 + (11/720)*n^6 + (167/720)*n^5 + (265/144)*n^4 + (5999/720)*n^3 + (974/45)*n^2 + (4191/140)*n + 19.
Conjectures from Colin Barker, May 28 2018: (Start)
G.f.: x*(81 - 378*x + 854*x^2 - 1148*x^3 + 966*x^4 - 502*x^5 + 148*x^6 - 19*x^7) / (1 - x)^8.
a(n) = 8*a(n-1) - 28*a(n-2) + 56*a(n-3) - 70*a(n-4) + 56*a(n-5) - 28*a(n-6) + 8*a(n-7) - a(n-8) for n>8.
(End)
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