cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A202411 a(n) = Sum_{k=floor(n/4)..R} C(k, m*k - (-1)^n*(R - k)) * C(k + 1, m*(k + 2) - (-1)^n*(R - k + 1)) where m = (n + 1) mod 2 and R = (n + m - 3)/2 for n > 0 and a(0) = 1.

Original entry on oeis.org

1, 0, 1, 1, 1, 2, 3, 4, 7, 10, 16, 24, 39, 58, 95, 143, 233, 354, 577, 881, 1436, 2204, 3590, 5534, 9011, 13940, 22691, 35213, 57299, 89162, 145043, 226238, 367931, 575114, 935078, 1464382, 2380405, 3734150, 6068745, 9534594, 15492702, 24374230, 39598631
Offset: 0

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Author

Peter Luschny, Jan 14 2012

Keywords

Examples

			Fibonacci meanders classified by maximal run length of 1s (see the link) lead to the triangle
   0,  1;
   1,  1,  0, 1;
   2,  1,  1, 1, 0, 1;
   4,  3,  2, 1, 1, 1, 0, 1;
  10,  7,  4, 3, 2, 1, 1, 1, 0, 1;
  24, 16, 10, 7, 4, 3, 2, 1, 1, 1, 0, 1.
		

Crossrefs

Programs

  • Maple
    A202411 := proc(n) local A, R, B, C, D, Z, H, J; if n = 0 then RETURN(1) fi;
    H:=iquo(n,2); A:=iquo(H,2); R:=H-1; B:=A-R/2+1; C:=A+1; D:=A-R; J:=n mod 2; if J = 0 then Z:=`if`(H mod 2 = 1,(H+1)/2,H^2*(H+2)/16) else Z:=`if`(H mod 2 = 1,1, H*(H+2)/4) fi; Z*hypergeom([1,C,C+1,D,D-J],[B,B,B-1/2,B+1/2-J],1/16) end:
    seq(simplify(A202411(i)),i=0..42);
  • Mathematica
    A202411[0] = 1; A202411[n_] := Module[{A, R, B, C, D, Z, H, J}, H = Quotient[n, 2]; A = Quotient[H, 2]; R = H-1; B = A - R/2 + 1; C = A+1; D = A - R; J = Mod[n, 2]; If[J == 0, Z = If[Mod[H, 2] == 1, (H+1)/2, H^2*(H + 2)/16], Z = If[Mod[H, 2] == 1, 1, H*(H+2)/4]]; Z*HypergeometricPFQ[{1, C, C + 1, D, D - J}, {B, B, B - 1/2, B + 1/2 - J}, 1/16]]; Table[A202411[n], {n, 0, 42}]
    (* Jean-François Alcover, Jan 27 2014, translated from Maple *)

Formula

For n > 0 let H = floor(n/2), A = floor(H/2), R = H - 1, B = A - R/2 + 1, C = A + 1, D = A - R, J = n mod 2 and Z = if(H mod 2 = 1, (H + 1)/2, H^2*(H + 2)/16) if J = 0 else Z = if(H mod 2 = 1, 1, H*(H + 2)/4); then:
a(n) = Z*Hypergeometric([1, C, C+1, D, D-J], [B, B, B-1/2, B+1/2-J], 1/16).