A203601 a(0)=1, a(n+1) = (a(n)*7) XOR a(n).
1, 6, 44, 280, 1712, 10336, 78528, 610688, 4745984, 28476928, 173222912, 1108678656, 6652604416, 48774012928, 292681859072, 1757200613376, 11780162781184, 70685271916544, 424730711293952, 3116299774853120, 19823698692276224, 120070359807426560, 720738827865423872
Offset: 0
Links
- Robert Israel, Table of n, a(n) for n = 0..1220
Crossrefs
Programs
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Maple
a[0]:= 1: for i from 1 to 50 do a[i]:= Bits:-Xor(a[i-1],a[i-1]*7) od: seq(a[i],i=0..50); # Robert Israel, Mar 22 2020
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Python
a=1 for n in range(55): print(a, end=',') a ^= a*7
Formula
a(0)=1, a(n+1) = (a(n)*7) XOR a(n), where XOR is the bitwise exclusive-or operator.
Comments