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A203838 a(n) = sigma_3(n)*Fibonacci(n), where sigma_3(n) = A001158(n), the sum of cubes of divisors of n.

%I A203838 #8 Jan 06 2018 13:24:50
%S A203838 1,9,56,219,630,2016,4472,12285,25738,62370,118548,294336,512134,
%T A203838 1167192,2152080,4620147,7847658,17604792,28681660,62224470,105431872,
%U A203838 212319468,348698376,759507840,1181718775,2401396326,4014783920,7980869832,12542045310
%N A203838 a(n) = sigma_3(n)*Fibonacci(n), where sigma_3(n) = A001158(n), the sum of cubes of divisors of n.
%C A203838 Compare g.f. to the Lambert series identity: Sum_{n>=1} n^3*x^n/(1-x^n) = Sum_{n>=1} sigma_3(n)*x^n.
%F A203838 G.f.: Sum_{n>=1} n^3*fibonacci(n)*x^n/(1 - Lucas(n)*x^n + (-1)^n*x^(2*n)) = Sum_{n>=1} sigma_3(n)*fibonacci(n)*x^n, where Lucas(n) = A000204(n).
%e A203838 G.f.: A(x) = x + 9*x^2 + 56*x^3 + 219*x^4 + 630*x^5 + 2016*x^6 +...
%e A203838 where A(x) = x/(1-x-x^2) + 2^3*1*x^2/(1-3*x^2+x^4) + 3^3*2*x^3/(1-4*x^3-x^6) + 4^3*3*x^4/(1-7*x^4+x^8) + 5^3*5*x^5/(1-11*x^5-x^10) + 6^3*8*x^6/(1-18*x^6+x^12) +...+ n^3*fibonacci(n)*x^n/(1 - Lucas(n)*x^n + (-1)^n*x^(2*n)) +...
%o A203838 (PARI) {a(n)=sigma(n,3)*fibonacci(n)}
%o A203838 (PARI) {Lucas(n)=fibonacci(n-1)+fibonacci(n+1)}
%o A203838 {a(n)=polcoeff(sum(m=1,n,m^3*fibonacci(m)*x^m/(1-Lucas(m)*x^m+(-1)^m*x^(2*m)+x*O(x^n))),n)}
%Y A203838 Cf. A203847, A203848, A203849, A001158 (sigma_3), A000204 (Lucas), A000045.
%K A203838 nonn
%O A203838 1,2
%A A203838 _Paul D. Hanna_, Jan 12 2012