A204202 Triangle based on (0,2/3,1) averaging array.
2, 2, 5, 2, 7, 11, 2, 9, 18, 23, 2, 11, 27, 41, 47, 2, 13, 38, 68, 88, 95, 2, 15, 51, 106, 156, 183, 191, 2, 17, 66, 157, 262, 339, 374, 383, 2, 19, 83, 223, 419, 601, 713, 757, 767, 2, 21, 102, 306, 642, 1020, 1314, 1470, 1524, 1535, 2, 23, 123, 408, 948
Offset: 1
Examples
First six rows: 2 2...5 2...7....11 2...9....18...23 2...11...27...41...47 2...13...38...68...88..95
Crossrefs
Cf. A204201.
Programs
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Mathematica
a = 0; r = 2/3; b = 1; t[1, 1] = r; t[n_, 1] := (a + t[n - 1, 1])/2; t[n_, n_] := (b + t[n - 1, n - 1])/2; t[n_, k_] := (t[n - 1, k - 1] + t[n - 1, k])/2; u[n_] := Table[t[n, k], {k, 1, n}] Table[u[n], {n, 1, 5}] (* averaging array *) u = Table[(1/r) 2^n*u[n], {n, 1, 12}]; TableForm[u] (* A204202 triangle *) Flatten[u] (* A204202 sequence *)
Formula
From Philippe Deléham, Dec 24 2013: (Start)
Sum_{k=1..n} T(n,k) = A066373(n+1).
T(n,k) = T(n-1,k)+3*T(n-1,k-1)-2*T(n-2,k-1)-2*T(n-2,k-2), T(1,1)=2, T(2,1)=2, T(2,2)=5, T(n,k)=0 if k<1 or if k>n. (End)
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