A207292 Polya-Vinogradov numbers A177865 for primes p == 3 (mod 4).
1, 2, 3, 3, 5, 6, 5, 8, 9, 6, 10, 10, 9, 10, 9, 10, 15, 9, 14, 9, 18, 15, 19, 18, 12, 15, 15, 22, 21, 21, 22, 13, 14, 25, 14, 17, 27, 19, 15, 27, 27, 30, 30, 18, 17, 21, 33, 19, 27, 17, 33, 19, 20, 27, 20, 22, 36, 26, 18, 26, 19, 36, 33, 23, 19, 41, 28, 23
Offset: 1
Keywords
Examples
The 2nd prime == 3 (mod 4) is 7 = prime(4), and A177865(4) = 2 (not 3, because the offset of A177865 is 2, not 1), so a(2) = 2.
Programs
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Mathematica
T = Table[Max[Table[Abs[Sum[JacobiSymbol[i, Prime[n]], {i, 1, k}]], {k, 1, Prime[n] - 1}]], {n, 2, 200}]; P = Table[Mod[Prime[n], 4], {n, 2, 200}]; Pick[T, P, 3]
Formula
a(n) = max_{0
Comments