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A208283 Number of n X 4 0..1 arrays avoiding 0 0 0 and 0 0 1 horizontally and 0 0 1 and 1 1 0 vertically.

%I A208283 #10 Jun 29 2018 11:23:55
%S A208283 10,100,378,984,2090,3900,6650,10608,16074,23380,32890,45000,60138,
%T A208283 78764,101370,128480,160650,198468,242554,293560,352170,419100,495098,
%U A208283 580944,677450,785460,905850,1039528,1187434,1350540,1529850,1726400,1941258
%N A208283 Number of n X 4 0..1 arrays avoiding 0 0 0 and 0 0 1 horizontally and 0 0 1 and 1 1 0 vertically.
%C A208283 Column 4 of A208287.
%H A208283 R. H. Hardin, <a href="/A208283/b208283.txt">Table of n, a(n) for n = 1..210</a>
%F A208283 Empirical: a(n) = (4/3)*n^4 + 10*n^3 + (2/3)*n^2 - 2*n.
%F A208283 Conjectures from _Colin Barker_, Jun 29 2018: (Start)
%F A208283 G.f.: 2*x*(5 + 25*x - 11*x^2 - 3*x^3) / (1 - x)^5.
%F A208283 a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5) for n>5.
%F A208283 (End)
%e A208283 Some solutions for n=4:
%e A208283 ..1..1..1..0....0..1..0..0....1..0..1..1....1..1..1..1....1..1..1..1
%e A208283 ..1..1..0..0....0..1..0..1....0..1..1..1....0..1..0..1....1..1..1..1
%e A208283 ..1..1..1..0....0..1..0..1....0..1..1..1....1..1..1..1....1..1..1..1
%e A208283 ..1..1..1..0....0..1..0..1....0..1..1..1....0..1..0..1....1..1..1..1
%Y A208283 Cf. A208287.
%K A208283 nonn
%O A208283 1,1
%A A208283 _R. H. Hardin_, Feb 25 2012