A209574 Triangle of coefficients of polynomials v(n,x) jointly generated with A209573; see the Formula section.

1, 2, 3, 3, 7, 5, 4, 14, 20, 7, 5, 24, 52, 45, 9, 6, 37, 110, 155, 86, 11, 7, 53, 203, 403, 389, 147, 13, 8, 72, 340, 882, 1240, 856, 232, 15, 9, 94, 530, 1712, 3204, 3322, 1702, 345, 17, 10, 119, 782, 3040, 7170, 10088, 7962, 3125, 490, 19, 11, 147, 1105

Offset: 1

Author

Clark Kimberling, Mar 11 2012

Keywords

• nonn
• tabl

Comments

Combinatorial limit of row n satisfies linear recurrence

r(n)=4*r(n-1)-r(n-2) with r(1)=1 and r(2)=3. For a

discussion and guide to related arrays, see A208510.

Examples

			First five rows:
1
2...3
3...7....5
4...14...20...7
5...24...52...45...9
First three polynomials v(n,x): 1, 2 + 3x , 3 + 7x + 5x^2.
		

Crossrefs

Cf. A209573, A208510.

Programs

Mathematica

u[1, x_] := 1; v[1, x_] := 1; z = 16;
u[n_, x_] := x*u[n - 1, x] + v[n - 1, x];
v[n_, x_] := 2 x*u[n - 1, x] + (x + 1)*v[n - 1, x] + 1;
Table[Expand[u[n, x]], {n, 1, z/2}]
Table[Expand[v[n, x]], {n, 1, z/2}]
cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
TableForm[cu]
Flatten[%]   (* A209573 *)
Table[Expand[v[n, x]], {n, 1, z}]
cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
TableForm[cv]
Flatten[%]   (* A209574 *)

Formula

u(n,x)=x*u(n-1,x)+v(n-1,x),

v(n,x)=2x*u(n-1,x)+(x+1)*v(n-1,x)+1,

where u(1,x)=1, v(1,x)=1.