A210598 Triangle of coefficients of polynomials u(n,x) jointly generated with A210599; see the Formula section.
1, 2, 2, 3, 7, 5, 4, 14, 23, 13, 5, 24, 58, 72, 34, 6, 36, 119, 219, 219, 89, 7, 51, 209, 521, 777, 653, 233, 8, 68, 338, 1048, 2101, 2639, 1918, 610, 9, 88, 508, 1902, 4754, 7989, 8679, 5567, 1597, 10, 110, 730, 3180, 9565, 20055, 29062, 27844, 16003
Offset: 1
Examples
First five rows: 1 2...2 3...7....5 4...14...23...13 5...24...58...72...34 First three polynomials u(n,x): 1, 2+ 2x, 3 + 7x + 5x^2.
Programs
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Mathematica
u[1, x_] := 1; v[1, x_] := 1; z = 16; u[n_, x_] := x*u[n - 1, x] + (x + 1)*v[n - 1, x] + 1; v[n_, x_] := (x + 1)*u[n - 1, x] + 2 x*v[n - 1, x] + 1; Table[Expand[u[n, x]], {n, 1, z/2}] Table[Expand[v[n, x]], {n, 1, z/2}] cu = Table[CoefficientList[u[n, x], x], {n, 1, z}]; TableForm[cu] Flatten[%] (* A210598 *) Table[Expand[v[n, x]], {n, 1, z}] cv = Table[CoefficientList[v[n, x], x], {n, 1, z}]; TableForm[cv] Flatten[%] (* A210599 *)
Formula
u(n,x)=x*u(n-1,x)+(x+1)*v(n-1,x),
v(n,x)=(x+1)*u(n-1,x)+2x*v(n-1,x)+1,
where u(1,x)=1, v(1,x)=1.
Comments