A210793 Triangle of coefficients of polynomials u(n,x) jointly generated with A210794; see the Formula section.

1, 2, 1, 3, 4, 2, 6, 10, 8, 3, 9, 24, 27, 16, 5, 18, 51, 74, 62, 30, 8, 27, 108, 189, 200, 136, 56, 13, 54, 216, 450, 574, 488, 282, 102, 21, 81, 432, 1026, 1536, 1571, 1128, 569, 184, 34, 162, 837, 2268, 3864, 4598, 3967, 2486, 1118, 328, 55, 243, 1620

Offset: 1

Author

Clark Kimberling, Mar 26 2012

Keywords

• nonn
• tabl

Comments

Row n starts with A038754(n) and ends with F(n), where F=A000045 (Fibonacci numbers).

Row sums: A000244 (powers of 3).

Alternating row sums: A000012 (1,1,1,1,1,1,1,1,1,1,1,...).

For a discussion and guide to related arrays, see A208510.

Subtriangle of the triangle given by (1, 1, -1, -1, 0, 0, 0, 0, 0, 0, 0, ...) DELTA (0, 1, 1, -1, 0, 0, 0, 0, 0, 0, 0, ...) where DELTA is the operator defined in A084938. - Philippe Deléham, Mar 29 2012

Examples

			First five rows:
  1;
  2,  1;
  3,  4,  2;
  6, 10,  8,  3;
  9, 24, 27, 16,  5;
First three polynomials u(n,x):
  1
  2 + x
  3 + 4x + 2x^2.
From _Philippe Deléham_, Mar 29 2012: (Start)
(1, 1, -1, -1, 0, 0, 0, ...) DELTA (0, 1, 1, -1, 0, 0, 0, ...) begins:
   1;
   1,  0;
   2,  1,  0;
   3,  4,  2,  0;
   6, 10,  8,  3,  0;
   9, 24, 27, 16,  5,  0;
  18, 51, 74, 62, 30,  8,  0; (End)
		

Crossrefs

Cf. A210794, A208510.

Programs

Mathematica

u[1, x_] := 1; v[1, x_] := 1; z = 16;
u[n_, x_] := u[n - 1, x] + (x + j)*v[n - 1, x] + c;
d[x_] := h + x; e[x_] := p + x;
v[n_, x_] := d[x]*u[n - 1, x] + e[x]*v[n - 1, x] + f;
j = 1; c = 0; h = 2; p = -1; f = 0;
Table[Expand[u[n, x]], {n, 1, z/2}]
Table[Expand[v[n, x]], {n, 1, z/2}]
cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
TableForm[cu]
Flatten[%]   (* A210793 *)
cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
TableForm[cv]
Flatten[%]   (* A210794 *)
Table[u[n, x] /. x -> 1, {n, 1, z}]   (* A000244 *)
Table[v[n, x] /. x -> 1, {n, 1, z}]   (* A000244 *)
Table[u[n, x] /. x -> -1, {n, 1, z}]  (* A000012 *)
Table[v[n, x] /. x -> -1, {n, 1, z}]  (* A077925 *)

Formula

u(n,x) = u(n-1,x) + (x+1)*v(n-1,x),

v(n,x) = (x+2)*u(n-1,x) + (x-1)*v(n-1,x),

where u(1,x)=1, v(1,x)=1.

From Philippe Deléham, Mar 29 2012: (Start)

As DELTA(triangle T(n,k) with 0 <= k <= n:

G.f.: (1 + x - y*x^2 - 2*y*x^2 - y^2*x^2)/(1 - y*x - 3*x^2 - 2*y*x^2 - y^2*x^2).

T(n,k) = T(n-1,k-1) + 3*T(n-2,k) + 2*T(n-2,k-1) + T(n-2,k-2), T(0,0) = T(1,0) = T(2,1) = 1, T(2,0) = 2, T(1,1) = T(2,2) = 0 and T(n,k) = 0 if k < 0 or if k <= n. (End)