cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A210886 Dates after Jan 01 1000 in chronological order which are palindromic when they are written in the format DDMMYYYY. Leading zeros of the terms are suppressed.

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%I A210886 #11 Apr 07 2014 00:36:47
%S A210886 10011001,20011002,30011003,1011010,11011011,21011012,31011013,
%T A210886 2011020,12011021,22011022,3011030,13011031,23011032,4011040,14011041,
%U A210886 24011042,5011050,15011051,25011052,6011060,16011061,26011062,7011070,17011071,27011072,8011080,18011081,28011082,9011090,19011091
%N A210886 Dates after Jan 01 1000 in chronological order which are palindromic when they are written in the format DDMMYYYY. Leading zeros of the terms are suppressed.
%C A210886 There are exactly 335 such palindromic dates between Jan 1 1000 and Dec 31 9999 (see b-file for the complete list).
%C A210886 See A210885 for the number of days after 'Jan 1 1000' to get such a palindromic date.
%C A210886 The first palindromic dates after 'Jan 01 2000' are 10022001, 20022002, 1022010, 11022011, 21022012, 2022020, 12022021, 22022022, 3022030, 13022031, 23022032, 4022040, 14022041, 24022042, 5022050, ... which are the 62nd, 63rd, ... 76th ... dates of the original sequence.
%H A210886 Hieronymus Fischer, <a href="/A210886/b210886.txt">Table of n, a(n) for n = 1..335</a>
%F A210886 a(n)=DDMMYYYY_date('Jan 1 1000' + A210885(n)).
%F A210886 n-th date after 'Jan 1 2000' = a(61+n).
%e A210886 The first palindromic date in DDMMYYYY format after 'Jan 01 1000' is a(1)=10011001 (= 'Jan 10 1001' = 'Jan 01 1000' + A210885(1) days);
%e A210886 The fourth palindromic date in DDMMYYYY format after 'Jan 01 1000' is a(4)=1011010=01011010 (= 'Jan 01 1010' = 'Jan 01 1000' + A210885(4) days);
%e A210886 The 66th palindromic date in DDMMYYYY format after 'Jan 01 1000' is a(66)=21022012 (= 'Feb 21 2012' = 'Jan 01 1000' + A210885(66) days)
%e A210886 The last (335th) palindromic date in DDMMYYYY format before the year 10000 is a(335)=29099092 (= 'Sep 29 9092' = 'Jan 01 1000' + A210885(335) days).
%Y A210886 Cf. A210883 - A210885, A210887 - A210895, A106605, A107273, A107275.
%K A210886 nonn,base
%O A210886 1,1
%A A210886 _Hieronymus Fischer_, Apr 01 2012