A210889 Number of days after Mar 01 00 such that the date written in the format D.M.YY (and considered as a number without the dots) is palindromic.

315, 346, 374, 405, 435, 466, 496, 527, 558, 619, 690, 721, 749, 780, 810, 841, 871, 902, 933, 994, 1065, 1124, 1155, 1185, 1216, 1246, 1277, 1308, 1369, 3958, 3968, 3999, 4027, 4058, 4088, 4119, 4149, 4180, 4211, 4231, 4262, 4272, 4292, 4324, 4343, 4374, 4403, 4434, 4464, 4495, 4525, 4556, 4587, 4598, 4629, 4648, 4659, 4691, 4719, 4778, 4839, 4900

Offset: 1

Author

Hieronymus Fischer, Apr 01 2012

Keywords

• nonn
• base

Comments

There are exactly 322 such palindromic dates between Mar 1 00 and Dec 31 99 (see b-file for the complete list).

See A210890 for the corresponding dates.

The definition is different from A210891 in that the dates are considered as numbers.

The reference date Mar 1 00 makes sense, since this definition results in a sequence which is independent from the leap year / non-leap year property of the reference year '00'.

Examples

			The first palindromic date in D.M.YY format after 'Jan 01 00' is A210890(1)=10101 (= '10.1.01' = 'Jan 10 01' = 'Mar 01 00' + 315 days);
The 10th palindromic date in D.M.YY format after 'Jan 01 00' is A210890(10)=101101 (= '10.11.01' = 'Nov 10 01' = 'Mar 01 00' + 619 days);
The 44th palindromic date in D.M.YY format after 'Jan 01 00' is A210890(44)=2112 (= '2.1.12' = 'Jan 2 12' = 'Mar 01 00' + 4324 days);
The last (322nd) palindromic date in D.M.YY format after 'Jan 01 00' is A210890(322)=9999 (= '9.9.99' = 'Sep 09 99' = 'Mar 01 00' + 36351 days).
		

Links

• Hieronymus Fischer, Table of n, a(n) for n = 1..322

Crossrefs

Cf. A210883-A210888, A210890-A210895, A106605, A107273, A107275.