A214370 If a(n) has not yet been defined then set a(n) = least positive integer that has not yet occurred; also if a(n+1+a(n)) has not yet been defined then set a(n+1+a(n)) = a(n).
1, 2, 1, 3, 2, 4, 5, 3, 6, 7, 4, 3, 5, 8, 9, 6, 10, 7, 5, 11, 12, 13, 8, 14, 9, 7, 15, 10, 16, 17, 18, 11, 19, 12, 9, 13, 20, 21, 14, 22, 23, 24, 15, 11, 9, 16, 12, 17, 25, 18, 26, 27, 19, 14, 9, 11, 28, 20, 15, 21, 29, 30, 22, 31, 23, 17, 24, 11, 18, 32, 33
Offset: 1
Examples
a(1) = 1 because this is the first undefined place and unused number. This "throws" a copy of the 1 forward to a(1+1+1)=a(3)=1. a(2)=2 uses the next new integer, and this copies the 2 forward to a(2+1+2)=a(5)=2. a(3) is already defined then, and a(4) receives the hitherto unused 3.
Programs
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Python
SIZE = 300 a = [-8]*SIZE top=0 for n in range(SIZE): if a[n]==-8: # if a[n] is undefined yet top+=1 a[n]=top if n+1+a[n]
Comments