A214458 - cp's OEIS frontend

A214458 Let S_3(n) denote difference between multiples of 3 in interval [0,n) with even and odd binary digit sums. Then a(n)=(-1)^A000120(n)(S_3(n)-3S_3(floor(n/4))).

n	a(n)
0	0
1	-1
2	-1
3	1
4	1
5	-1
6	-1
7	0
8	0
9	0
10	1
11	-1
12	1
13	-2
14	-2
15	2
16	0
17	0
18	0
19	-1
20	1
21	-1
22	0
23	0
24	0
25	-1
26	-1
27	1
28	1
29	-1
30	-1
31	0
32	0
33	0
34	1
35	-1
36	1
37	-2
38	-2
39	2
40	0
41	0
42	0
43	-1
44	1
45	-1
46	0
47	0
48	0
49	-1
50	-1
51	1
52	1
53	-1
54	-1
55	0
56	0
57	0
58	1
59	-1
60	1
61	-2
62	-2
63	2
64	0
65	0
66	0
67	-1
68	1
69	-1
70	0
71	0
72	0
73	-1
74	-1
75	1
76	1

[0, -1, -1, 1, 1, -1, -1, 0, 0, 0, 1, -1, 1, -2, -2, 2, 0, 0, 0, -1, 1, -1, 0, 0, 0, -1, -1, 1, 1, -1, -1, 0, 0, 0, 1, -1, 1, -2, -2, 2, 0, 0, 0, -1, 1, -1, 0, 0, 0, -1, -1, 1, 1, -1, -1, 0, 0, 0, 1, -1, 1, -2, -2, 2, 0, 0, 0, -1, 1, -1, 0, 0, 0, -1, -1, 1, 1]

cp's OEIS Frontend

A214458 Let S_3(n) denote difference between multiples of 3 in interval [0,n) with even and odd binary digit sums. Then a(n)=(-1)^A000120(n)(S_3(n)-3S_3(floor(n/4))).

Table of values

List of values

n	a(n)
0	0
1	-1
2	-1
3	1
4	1
5	-1
6	-1
7	0
8	0
9	0
10	1
11	-1
12	1
13	-2
14	-2
15	2
16	0
17	0
18	0
19	-1
20	1
21	-1
22	0
23	0
24	0
25	-1
26	-1
27	1
28	1
29	-1
30	-1
31	0
32	0
33	0
34	1
35	-1
36	1
37	-2
38	-2
39	2
40	0
41	0
42	0
43	-1
44	1
45	-1
46	0
47	0
48	0
49	-1
50	-1
51	1
52	1
53	-1
54	-1
55	0
56	0
57	0
58	1
59	-1
60	1
61	-2
62	-2
63	2
64	0
65	0
66	0
67	-1
68	1
69	-1
70	0
71	0
72	0
73	-1
74	-1
75	1
76	1

n	a(n)
0	0
1	-1
2	-1
3	1
4	1
5	-1
6	-1
7	0
8	0
9	0
10	1
11	-1
12	1
13	-2
14	-2
15	2
16	0
17	0
18	0
19	-1
20	1
21	-1
22	0
23	0
24	0
25	-1
26	-1
27	1
28	1
29	-1
30	-1
31	0
32	0
33	0
34	1
35	-1
36	1
37	-2
38	-2
39	2
40	0
41	0
42	0
43	-1
44	1
45	-1
46	0
47	0
48	0
49	-1
50	-1
51	1
52	1
53	-1
54	-1
55	0
56	0
57	0
58	1
59	-1
60	1
61	-2
62	-2
63	2
64	0
65	0
66	0
67	-1
68	1
69	-1
70	0
71	0
72	0
73	-1
74	-1
75	1
76	1

cp's OEIS Frontend

A214458 Let S_3(n) denote difference between multiples of 3 in interval [0,n) with even and odd binary digit sums. Then a(n)=(-1)^A000120(n)*(S_3(n)-3*S_3(floor(n/4))).

Table of values

List of values

A214458 Let S_3(n) denote difference between multiples of 3 in interval [0,n) with even and odd binary digit sums. Then a(n)=(-1)^A000120(n)(S_3(n)-3S_3(floor(n/4))).

n	a(n)
0	0
1	-1
2	-1
3	1
4	1
5	-1
6	-1
7	0
8	0
9	0
10	1
11	-1
12	1
13	-2
14	-2
15	2
16	0
17	0
18	0
19	-1
20	1
21	-1
22	0
23	0
24	0
25	-1
26	-1
27	1
28	1
29	-1
30	-1
31	0
32	0
33	0
34	1
35	-1
36	1
37	-2
38	-2
39	2
40	0
41	0
42	0
43	-1
44	1
45	-1
46	0
47	0
48	0
49	-1
50	-1
51	1
52	1
53	-1
54	-1
55	0
56	0
57	0
58	1
59	-1
60	1
61	-2
62	-2
63	2
64	0
65	0
66	0
67	-1
68	1
69	-1
70	0
71	0
72	0
73	-1
74	-1
75	1
76	1