A215099 a(0)=0, a(1)=1, a(n) = least k>a(n-1) such that k+a(n-2) is prime.
0, 1, 2, 4, 5, 7, 8, 10, 11, 13, 18, 24, 25, 29, 34, 38, 39, 41, 44, 48, 53, 55, 56, 58, 71, 73, 78, 84, 85, 89, 94, 102, 103, 109, 120, 124, 131, 133, 138, 144, 145, 149, 162, 164, 169, 173, 178, 180, 181, 187, 192, 196, 197, 201
Offset: 0
Keywords
Links
- Iain Fox, Table of n, a(n) for n = 0..10000
Crossrefs
Programs
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PARI
first(n) = my(res = vector(n, i, i-1), k); for(x=3, n, k=res[x-1]+1; while(!isprime(k+res[x-2]), k++); res[x]=k); res \\ Iain Fox, Apr 22 2019 (corrected by Iain Fox, Apr 25 2019)
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Python
from sympy import prime prpr = 0 prev = 1 for n in range(77): print(prpr, end=', ') b = c = 0 while c<=prev: c = prime(b+1) - prpr b+=1 prpr = prev prev = c
Comments