A215256 Longest palindromic factor of (n base 2); in case of tie choose largest; if it begins with 0 complement it.
1, 1, 1, 11, 11, 101, 11, 111, 111, 1001, 101, 101, 11, 101, 111, 1111, 1111, 10001, 1001, 1001, 101, 10101, 1001, 111, 111, 1001, 101, 11011, 111, 111, 1111, 11111, 11111, 100001, 10001, 10001, 11011, 1001, 1001, 1001, 101, 1001, 10101, 10101, 1001, 101101
Offset: 0
Examples
n=10 = 1010, longest palindromic factor is 101. n=12 = 1100, there are two palindromic factors of length 2, namely 11 and 00, and we choose the larger, 11. n=24 = 11000, longest palindromic factor is 000, complementing gives 111.
Links
- Lars Blomberg, Table of n, a(n) for n = 0..9999
Extensions
More terms from Lars Blomberg, Jun 29 2014
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