A215604 a(0)=0, a(n) = (n + a(floor(n/2))) mod 3.
0, 1, 0, 1, 1, 2, 1, 2, 0, 1, 0, 1, 1, 2, 1, 2, 1, 2, 1, 2, 2, 0, 2, 0, 1, 2, 1, 2, 2, 0, 2, 0, 0, 1, 0, 1, 1, 2, 1, 2, 0, 1, 0, 1, 1, 2, 1, 2, 1, 2, 1, 2, 2, 0, 2, 0, 1, 2, 1, 2, 2, 0, 2, 0, 1, 2, 1, 2, 2, 0, 2, 0, 1, 2, 1, 2, 2, 0, 2, 0, 2, 0, 2, 0, 0, 1, 0, 1, 2
Offset: 0
Crossrefs
Programs
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Python
TOP = 1000 a = [0]*TOP for n in range(1, TOP): print(a[n-1], end=', ') a[n] = (n + a[n//2]) % 3