A216045 Numbers k such that Sum_{j=1..k-1} (4j)!/5^j is an integer.
1, 6, 30, 145, 151, 592, 732, 3895, 87806, 292432
Offset: 1
Programs
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Mathematica
seq={}; sum=0; fak=1; k=0; While[k<10000, sum+=fak; If[Denominator[sum]==1, AppendTo[seq,k+1]]; k++; fak*=4*k*(4*k-1)*(4*k-2)*(4*k-3)/5;]; seq
Comments