cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-6 of 6 results.

A217287 Length of chain of consecutive integers starting with n, where each new integer in the chain has a prime factor which no previous member in the chain has.

Original entry on oeis.org

3, 2, 3, 4, 3, 2, 5, 4, 3, 5, 5, 4, 3, 2, 3, 8, 7, 6, 5, 4, 3, 5, 4, 3, 5, 6, 5, 4, 3, 2, 5, 4, 3, 6, 5, 9, 8, 7, 6, 5, 7, 6, 5, 4, 3, 8, 7, 6, 5, 4, 3, 8, 7, 6, 5, 7, 7, 6, 5, 4, 3, 2, 7, 8, 7, 6, 5, 4, 3, 5, 9, 8, 7, 6, 5, 5, 4, 3, 11, 10, 9, 8, 7, 6, 5, 10, 9, 8, 7, 6, 5, 4, 3, 6, 5, 9, 8, 7, 9, 8
Offset: 1

Views

Author

Lior Manor, Sep 30 2012

Keywords

Comments

a(n) >= 2. If n < 2 is prime or prime power, a(n) >= 3. For any n > 1, k > 1, a(n^k - n) <= n.
a(n) is also the smallest k>0 such that n+k is k-smooth (i.e. has no prime factor > k). - N. J. A. Sloane, Apr 25 2020

Examples

			Example: a(7)=5 since 7 starts a chain of 5 integers 7-11 with the following property: 7 is divisible by 7, 8 is divisible by 2, 9 is divisible by 3, 10 is divisible by 5, 11 is divisible by 11. And the next integer 12 is divisible by 2 and 3, both of them are prime factors of prior members in the chain.
		

Crossrefs

Cf. A006530, A217288 and A217289 (records), A217438.

Programs

  • Maple
    A006530 := n->max(1, op(numtheory[factorset](n)));
    a:=[]; M:=120;
    for n from 1 to M do
       for k from 1 to 3*n do
       if A006530(n+k) <= k then a:=[op(a),k]; break; fi;
       od;
    od:
    a; # N. J. A. Sloane, Apr 25 2020
  • Mathematica
    Block[{nn = 111, r}, r = Prime@ Range[PrimePi@ nn]; r = Table[FromDigits[#, 2] &@ Map[Boole[Mod[n, #] == 0] &, r], {n, nn}]; Array[Block[{k = # + 1, s = r[[#]]}, While[UnsameQ[s, Set[s, BitOr[s, r[[k]] ] ] ], k++]; k - #] &, nn - Ceiling@ Sqrt@ nn] ] (* Michael De Vlieger, Apr 30 2020 *)

Extensions

a(1) = 3 added by N. J. A. Sloane, Apr 25 2020

A217288 Records in A217287.

Original entry on oeis.org

3, 4, 5, 8, 9, 11, 14, 18, 19, 20, 22, 25, 30, 32, 35, 38, 41, 45, 46, 49, 52, 54, 62, 68, 72, 73, 74, 85, 86, 88, 90, 105, 110, 112, 126, 128, 143, 144, 149, 154, 161, 166, 182
Offset: 1

Views

Author

Lior Manor, Sep 30 2012

Keywords

Crossrefs

Extensions

Beginning changed because of new term a(1)=3 in A217287. - N. J. A. Sloane, Apr 25 2020

A217289 Where records occur in A217287.

Original entry on oeis.org

1, 4, 7, 16, 36, 79, 106, 222, 456, 460, 650, 1046, 1090, 2110, 2205, 2302, 3455, 4946, 6072, 6671, 10388, 12000, 12174, 24772, 26790, 29490, 36862, 39767, 72361, 79240, 86810, 87580, 135014, 172256, 210917, 223312, 293452, 538746, 550786, 585886, 617819, 838074, 879410
Offset: 1

Views

Author

Lior Manor, Sep 30 2012

Keywords

Crossrefs

Extensions

Beginning changed because of new term a(1)=3 in A217287. - N. J. A. Sloane, Apr 25 2020

A334468 List of distinct values of n + A217287(n).

Original entry on oeis.org

4, 6, 8, 12, 15, 16, 18, 24, 27, 30, 32, 36, 40, 45, 48, 54, 60, 63, 64, 70, 72, 75, 80, 81, 90, 96, 100, 105, 108, 120, 125, 128, 135, 140, 144, 150, 160, 162, 168, 175, 180, 189, 192, 200, 210, 216, 224, 225, 234, 240, 243, 250, 256, 270, 280, 288, 294, 300
Offset: 1

Views

Author

Michael De Vlieger, May 02 2020

Keywords

Comments

This sequence is a list of primitive least m > n whose distinct prime factors p are not a subset of those prime factors p found in the range n..(m - 1), i.e., the smallest A217287(n)-smooth number m > n. These numbers serve as "obstructions" that end or break the chains described at A217287.
The number (a(n) - 1) can be found in at least one row of A217438. In other words, this sequence includes any number T(n, A217287(n)) + 1 where T(n, k) is the irregular triangle described at A217438.

Examples

			Start with n = 1, the empty product. Incrementing n and storing the distinct prime factors each time, we encounter 2, which does not divide any previous number n. Therefore we proceed to n = 3, which is prime and its distinct prime divisor again does not divide any previous number. Finally, at 4, we have the distinct prime divisor 2, since 2 divides the product of the previous range {1, 2, 3}, we end the chain. Therefore 4 is the first term of this sequence.
We list row n of A217438 below, starting with n aligned in columns:
1  2  3
   2  3
      3  4  5
         4  5  6  7
            5  6  7
               6  7
                  7  8  9  10  11
                     8  9  10  11
                        9  10  11
                           10  11  12  13  14
                               11  12  13  14  15
                                   12  13  14  15
                                       13  14  15
                                           14  15
                                               ...
Adding 1 to the last numbers seen in all the rows and considering each value only once, we generate the sequence {4, 6, 8, 12, 15, 16, ...}
		

Crossrefs

Programs

  • Mathematica
    Block[{nn = 2^9, r}, r = Array[If[# == 1, 0, Total[2^(PrimePi /@ FactorInteger[#][[All, 1]] - 1)]] &, nn + Ceiling@ Sqrt@ nn]; Union@ Array[Block[{k = # + 1, s = r[[#]]}, While[UnsameQ[s, Set[s, BitOr[s, r[[k]] ] ] ], k++]; k] &, nn] ]

Formula

a(n) > n + 2 for all n.
a(m) = m + 2 for m = 2^k - 2 and k > 1, since m is even and 2^k only has the distinct prime divisor 2. Therefore 2^k for k > 1 is in this sequence.

A334469 Indices of zero or positive first differences in A217287.

Original entry on oeis.org

1, 3, 4, 7, 10, 11, 15, 16, 22, 25, 26, 31, 34, 36, 41, 46, 52, 56, 57, 63, 64, 70, 71, 76, 79, 86, 94, 96, 99, 106, 116, 121, 127, 131, 134, 142, 146, 156, 160, 162, 169, 176, 183, 190, 196, 204, 214, 218, 221, 222, 236, 241, 246, 255, 266, 274, 286, 288, 296
Offset: 1

Views

Author

Michael De Vlieger, May 02 2020

Keywords

Comments

Starting with i, we increment i to build a chain of consecutive numbers such that all distinct prime factors of ensuing numbers i + 1, i + 2, etc., divide at least one previous number in the chain. We store the chains in an irregular triangle T(i,j) described in A217438.
This sequence lists rows i such that the last term exceeds that of the previous row.

Examples

			We list numbers in row i of A217438 below, starting with i, aligned in columns:
1  2  3
   2  3
      3  4  5
         4  5  6  7
            5  6  7
               6  7
                  7  8  9  10  11
                     8  9  10  11
                        9  10  11
                           10  11  12  13  14
                               11  12  13  14  15
                                   12  13  14  15
                                       13  14  15
                                           14  15
1 is in the sequence since it is the first row.
2 is not in the sequence, since the last term (3) in row 2 of A217438 is equal to that of the previous row.
3 is in the sequence since its last term (5) exceeds that of the previous row (3).
Further, we observe the terms in row i breaking through resistance in the previous row at i = {1, 3, 4, 7, 10, 11, ...}
		

Crossrefs

Programs

  • Mathematica
    Block[{nn = 2^9, r}, r = Array[If[# == 1, 0, Total[2^(PrimePi /@ FactorInteger[#][[All, 1]] - 1)]] &, nn]; Position[Prepend[#, 1], _?(# > 0 &)][[All, 1]] &@ Differences@ Array[Block[{k = # + 1, s = r[[#]]}, While[UnsameQ[s, Set[s, BitOr[s, r[[k]] ] ] ], k++]; k] &, nn - Ceiling@ Sqrt@ nn] ]

A333518 a(n) = A000720(A006530(A334468(n))).

Original entry on oeis.org

1, 2, 1, 2, 3, 1, 2, 2, 2, 3, 1, 2, 3, 3, 2, 2, 3, 4, 1, 4, 2, 3, 3, 2, 3, 2, 3, 4, 2, 3, 3, 1, 3, 4, 2, 3, 3, 2, 4, 4, 3, 4, 2, 3, 4, 2, 4, 3, 6, 3, 2, 3, 1, 3, 4, 2, 4, 3, 5, 6, 4, 3, 2, 4, 4, 4, 3, 7, 3, 4, 2, 4, 3, 3, 6, 4, 6, 2, 4, 4, 3, 5, 6, 8, 7, 3, 2, 5, 3, 4, 1, 4, 5, 3, 5, 4, 4, 2, 4, 5, 3, 5, 6, 3, 4
Offset: 1

Views

Author

Michael De Vlieger, May 05 2020

Keywords

Comments

Indices of the greatest prime factor of A334468(n).
Consider A334468, a list of numbers m = n+j such that j > 0 is also the smallest number such that n+j has no prime factor > j for some n and j = A217287(n).
Since prime q always contributes a novel prime divisor (i.e., q itself) to the set of distinct primes that divide at least 1 number i the range n + i (1 <= i <= j), the numbers m in A334468 are composite, and given the above, m is a product of relatively small prime factors.

Examples

			Start with n = 1, the empty product. Incrementing n and storing the distinct prime factors each time, we encounter 2, which does not divide any previous number n. Therefore we proceed to n = 3, which is prime and its distinct prime divisor again does not divide any previous number. Finally, at 4, we have the distinct prime divisor 2, since 2 divides the product of the previous range {1, 2, 3}, we end the chain. Therefore 4 is the first term of this sequence.
We list row n of A217438 below, starting with n aligned in columns:
1  2  3
   2  3
      3  4  5
         4  5  6  7
            5  6  7
               6  7
                  7  8  9  10  11
                     8  9  10  11
                        9  10  11
                           10  11  12  13  14
                               11  12  13  14  15
                                   12  13  14  15
                                       13  14  15
                                           14  15
                                               ...
Adding 1 to the last numbers seen in all the rows, we generate the sequence A334468: {4, 6, 8, 12, 15, 16, ...}. Of these, we have greatest prime factors {2, 3, 2, 3, 5, 2, ...} with indices {1, 2, 1, 2, 3, 1, ...}.
Least indices of prime(k) in a(n):
   i  p(i)    n    a(n)
  ---------------------
   1    2     1      4
   2    3     2      6
   3    5     5     15
   4    7    18     63
   5   11    59    308
   6   13    49    234
   7   17    68    374
   8   19    84    475
   9   23   292   2392
  10   29   401   3625
  11   31   518   4991
  12   37   791   8547
  ...
		

Crossrefs

Programs

  • Mathematica
    Block[{nn = 2^10, r}, r = Array[If[# == 1, 0, Total[2^(PrimePi /@ FactorInteger[#][[All, 1]] - 1)]] &, nn]; Map[PrimePi@ FactorInteger[#][[-1, 1]] &, #] &@ Union@ Array[Block[{k = # + 1, s = r[[#]]}, While[UnsameQ[s, Set[s, BitOr[s, r[[k]] ] ] ], k++]; k] &, nn - Ceiling@ Sqrt@ nn] ]
Showing 1-6 of 6 results.