A217884 - cp's OEIS frontend

A217884 Let c(m)=prime(m), m=1,2,3,4. For m>=5, suppose that c(m)/e is in the interval [c(k),c(k+1)). Then let c(m+1)=ec(k+1) if ec(k+1) < prime(m+1), and otherwise let c(m+1) = prime(m+1). Then a(n) is the n-th prime in {c(m)}.

n	a(n)
1	2
2	3
3	5
4	7
5	13
6	19
7	31
8	43
9	47
10	67
11	71
12	73
13	79
14	83
15	103
16	107
17	109
18	113
19	137
20	139
21	157
22	163
23	173
24	179
25	181
26	197
27	211
28	229
29	239
30	241
31	251
32	257
33	269
34	271
35	283
36	313
37	317
38	337
39	347
40	353
41	359
42	367
43	397
44	401
45	409
46	419

[2, 3, 5, 7, 13, 19, 31, 43, 47, 67, 71, 73, 79, 83, 103, 107, 109, 113, 137, 139, 157, 163, 173, 179, 181, 197, 211, 229, 239, 241, 251, 257, 269, 271, 283, 313, 317, 337, 347, 353, 359, 367, 397, 401, 409, 419]

cp's OEIS Frontend

A217884 Let c(m)=prime(m), m=1,2,3,4. For m>=5, suppose that c(m)/e is in the interval [c(k),c(k+1)). Then let c(m+1)=ec(k+1) if ec(k+1) < prime(m+1), and otherwise let c(m+1) = prime(m+1). Then a(n) is the n-th prime in {c(m)}.

Table of values

List of values

n	a(n)
1	2
2	3
3	5
4	7
5	13
6	19
7	31
8	43
9	47
10	67
11	71
12	73
13	79
14	83
15	103
16	107
17	109
18	113
19	137
20	139
21	157
22	163
23	173
24	179
25	181
26	197
27	211
28	229
29	239
30	241
31	251
32	257
33	269
34	271
35	283
36	313
37	317
38	337
39	347
40	353
41	359
42	367
43	397
44	401
45	409
46	419

n	a(n)
1	2
2	3
3	5
4	7
5	13
6	19
7	31
8	43
9	47
10	67
11	71
12	73
13	79
14	83
15	103
16	107
17	109
18	113
19	137
20	139
21	157
22	163
23	173
24	179
25	181
26	197
27	211
28	229
29	239
30	241
31	251
32	257
33	269
34	271
35	283
36	313
37	317
38	337
39	347
40	353
41	359
42	367
43	397
44	401
45	409
46	419

cp's OEIS Frontend

A217884 Let c(m)=prime(m), m=1,2,3,4. For m>=5, suppose that c(m)/e is in the interval [c(k),c(k+1)). Then let c(m+1)=e*c(k+1) if e*c(k+1) < prime(m+1), and otherwise let c(m+1) = prime(m+1). Then a(n) is the n-th prime in {c(m)}.

Table of values

List of values

A217884 Let c(m)=prime(m), m=1,2,3,4. For m>=5, suppose that c(m)/e is in the interval [c(k),c(k+1)). Then let c(m+1)=ec(k+1) if ec(k+1) < prime(m+1), and otherwise let c(m+1) = prime(m+1). Then a(n) is the n-th prime in {c(m)}.

n	a(n)
1	2
2	3
3	5
4	7
5	13
6	19
7	31
8	43
9	47
10	67
11	71
12	73
13	79
14	83
15	103
16	107
17	109
18	113
19	137
20	139
21	157
22	163
23	173
24	179
25	181
26	197
27	211
28	229
29	239
30	241
31	251
32	257
33	269
34	271
35	283
36	313
37	317
38	337
39	347
40	353
41	359
42	367
43	397
44	401
45	409
46	419