A223859 Number of n X 3 0..3 arrays with rows and antidiagonals unimodal and columns nondecreasing.
50, 684, 4884, 24199, 93731, 303560, 857696, 2175884, 5058530, 10940664, 22267210, 43028893, 79505879, 141274716, 242543322, 403888650, 654482250, 1034900244, 1600626232, 2426368355, 3611325155, 5285548992, 7617570604, 10823463928
Offset: 1
Keywords
Examples
Some solutions for n=3: ..2..1..1....0..3..0....2..2..0....1..1..1....0..1..0....0..0..1....2..1..0 ..3..2..1....3..3..2....2..3..1....3..2..2....0..2..1....0..0..2....3..3..3 ..3..3..1....3..3..2....2..3..1....3..3..3....1..3..1....0..1..3....3..3..3
Links
- R. H. Hardin, Table of n, a(n) for n = 1..210
Crossrefs
Cf. A223864.
Formula
Empirical: a(n) = (353/181440)*n^9 + (353/10080)*n^8 + (9707/30240)*n^7 + (13/8)*n^6 + (45713/8640)*n^5 + (1809/160)*n^4 + (332021/22680)*n^3 + (6569/504)*n^2 + (7241/1260)*n - 2.
Conjectures from Colin Barker, Aug 24 2018: (Start)
G.f.: x*(50 + 184*x + 294*x^2 + 139*x^3 - 59*x^4 + 165*x^5 - 117*x^6 + 66*x^7 - 18*x^8 + 2*x^9) / (1 - x)^10.
a(n) = 10*a(n-1) - 45*a(n-2) + 120*a(n-3) - 210*a(n-4) + 252*a(n-5) - 210*a(n-6) + 120*a(n-7) - 45*a(n-8) + 10*a(n-9) - a(n-10) for n>10.
(End)
Comments