A224444 Multiplicities for representations of nonnegative numbers as primitive sums of three squares of integers (square 0 allowed).
0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 2, 1, 1, 0, 1, 1, 0, 0, 1, 2, 1, 0, 2, 1, 0, 0, 2, 2, 1, 0, 1, 2, 0, 0, 3, 1, 1, 0, 1, 1, 0, 0, 1, 2, 2, 0, 2, 2, 0, 0, 2, 1, 2, 0, 2, 2, 0, 0, 3, 3, 1, 0, 2, 1, 0, 0, 2, 3, 1, 0, 2, 1, 0, 0, 2, 2, 2, 0, 2, 3, 0, 0, 4, 2, 1, 0, 1, 2, 0, 0, 2, 2, 2, 0, 4, 2, 0, 0, 2, 2, 2, 0, 2, 3, 0, 0, 3, 3, 1, 0, 2, 2, 0, 0, 2, 3, 2, 0, 3
Offset: 0
Keywords
Examples
a(0) = 0 because 0 = 0^2 + 0^2 + 0^2 is the only candidate for a representation but this is not a primitive sum because gcd(0,0,0) = 0, not 1. a(2) = 1 because the only candidate for a representation of 2 is the triple [a,b,c] = [0,1,1] and this is primitive, because gcd(0,1,1) = 1. a(9) = 1 because the two candidate triples are [0, 0, 3] and [1, 2, 2] but [0, 0, 3] is not primitive (gcd(0,0,3) = 3). A000164(9) = 2. a(17) = 2 with the primitive [a,b,c] triples [0, 1, 4] and [2, 2, 3]. A000164(17) = 2 also. a(41) = 3 = A000164(41) because the candidate triples [0, 4, 5], [1, 2, 6] and [3, 4, 4] are all primitive.
Programs
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Mathematica
Table[ Count[ PowersRepresentations[n, 3, 2], pr_ /; GCD @@ pr == 1], {n, 0, 125}] (* Jean-François Alcover, Apr 09 2013 *)
Formula
a(n) = k if n, for n >= 0, has exactly k representations n = a^2 + b^2 + c^2, with a, b and c integers, 0 <= a <= b < = c and gcd(a,b,c) = 1. If there is no such representation a(n) = 0.
Comments