A225871 Number of people required for there to be a 50% probability that at least 4 share a birthday in a year with n days.

4, 6, 7, 9, 10, 11, 12, 13, 15, 16, 17, 18, 18, 19, 20, 21, 22, 23, 24, 25, 25, 26, 27, 28, 28, 29, 30, 31, 32, 32, 33, 34, 34, 35, 36, 37, 37, 38, 39, 39, 40, 41, 41, 42, 43, 43, 44, 45, 45, 46, 46, 47, 48, 48, 49, 50, 50, 51, 51, 52, 53, 53, 54, 54, 55, 56

Offset: 1

Author

Kevin L. Schwartz and Christian N. K. Anderson, May 18 2013

Keywords

• nonn

Comments

a(365)=187.

For n<1000, the formula a(n) = 2.79 + 2.456*n^0.732 - 1.825/n provides an estimate of a(n) accurate to 0.82.

Examples

			For a year with 365 days, a(365), the probability that out of 186 people 4 of them share a birthday is 0.495825. The corresponding probability for 187 people is 0.502685, and therefore a(365)=187.
		

Links

• Christian N. K. Anderson, Table of n, a(n) for n = 1..1000
• Christian N. K. Anderson, Table of n, exact probabilities of a(n)-1 and a(n) for n = 1..1000.
• Patrice Le Conte, Coincident Birthdays

Crossrefs

Cf. A014088 (n people on 365 days), A033810 (2 people on n days), A225852 (3 on n days).

Cf. A088141, A182008, A182009, A182010.

Programs

R

library(gmp);#prob of a maximum of exactly k coincident birthdays is
BigQ<-function(nday,p,k) { #nday=days in a year; p=people
    if(p1,sum(sapply(2:k-1,function(j) BigQ(nday-i,p-k*i,j))),1)
    }
    tot
}
BDaySharedByAtLeast<-function(nday,people,k) {
    if(nday<1 | people