A228036 (10^n)-th primitive antiharmonic number.

1, 605, 51005, 5837732, 599407380, 60462121402

Offset: 0

Author

Jonathan Sondow and Charles R Greathouse IV, Aug 04 2013

Keywords

• nonn

Comments

We conjecture that lim_{n->oo} a(n)/100^n = lim_{n->oo} A228023(n)/n^2 = 6. This is supported by the values a(n)/(10^n)^2 = 6.05, 5.10, 5.84, 5.99, 6.05 for n = 1..5, as well as by the values of A228023(n)/n^2.

Crossrefs

Cf. A020487, A227771, A228023, A228024.

Formula

a(n) = A228023(10^n).

Extensions

a(5) from Charles R Greathouse IV, Sep 03 2013