A229862 Let sigma*_m (n) be result of applying sum of anti-divisors m times to n; call n (m,k)-anti-perfect if sigma*_m (n) = k*n; sequence gives the (4,k)-anti-perfect numbers.
5, 6, 7, 8, 14, 16, 41, 46, 56, 58, 64, 92, 96, 114, 946, 3307, 3325, 5186, 5566, 6596, 6874, 7982, 8104, 14621, 17386, 27024, 44217, 45970, 84026, 91282, 135592, 167786, 1077378, 1231058, 1529394, 2667584, 2873910, 3098834, 3978336, 4292594, 4921776, 27914146
Offset: 1
Keywords
Examples
Anti-divisors of 58 are 3, 4, 5, 9, 13, 23, 39. Their sum is 96. The only anti-divisor of 96 is 64. Again, anti-divisors of 64 are 3, 43. Their sum is 46. Finally, anti-divisors of 46 are 3, 4, 7, 13, 31. Their sum is 58 and 58 / 58 = 1.
Programs
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Maple
with(numtheory); P:=proc(q,h) local a,i,j,k,n; for n from 5 to q do a:=n; for i from 1 to h do k:=0; j:=a; while j mod 2 <> 1 do k:=k+1; j:=j/2; od; a:=sigma(2*a+1)+sigma(2*a-1)+sigma(a/2^k)*2^(k+1)-6*a-2; od; if type(a/n,integer) then print(n); fi; od; end: P(10^6,4);
Extensions
Offset corrected and a(33)-a(42) from Donovan Johnson, Jan 09 2014
Comments