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A229941 Sequence of triples: the 10 solutions of 1/p + 1/q + 1/r = 1/2 with 0 < p <= q <= r, lexicographically sorted.

%I A229941 #33 Apr 29 2019 01:34:45
%S A229941 3,7,42,3,8,24,3,9,18,3,10,15,3,12,12,4,5,20,4,6,12,4,8,8,5,5,10,6,6,6
%N A229941 Sequence of triples: the 10 solutions of 1/p + 1/q + 1/r = 1/2 with 0 < p <= q <= r, lexicographically sorted.
%C A229941 As noted by John Baez, "each of [the 10 solutions of 1/p + 1/q + 1/r = 1/2] gives a way for three regular polygons to snugly meet at a point".
%C A229941 Among the 14 4-term Egyptian fractions with unit sum, there are 10 of the form 1/2 + 1/p + 1/q + 1/r.
%C A229941 Also integer values of length, width and height of a rectangular prism whose surface area is equal to its volume: pqr = 2(pq+pr+qr). - _John Rafael M. Antalan_, Jul 05 2015
%H A229941 John Baez, <a href="http://www.math.ucr.edu/home/baez/42.html">The answer is 42.</a>
%H A229941 J. F. T. Rabago and R. P. Tagle, <a href="http://nntdm.net/volume-19-2013/number-3/28-32/">On the Area and Volume of a certain Rectangular Solid and the Diophantine Equation 1/2=1/x+1/y+1/z</a>, Notes on Number Theory and Discrete Mathematics, 19-3 (2013), 28-32.
%H A229941 Wikipedia, <a href="http://en.wikipedia.org/wiki/Hurwitz%27s_automorphisms_theorem">Hurwitz's automorphisms theorem.</a>
%e A229941 a(1) = 3, a(2) = 7, a(3) = 42, since 1/3 + 1/7 + 1/42 = 1/2.
%e A229941 The 10 solutions are:
%e A229941 3,  7, 42;
%e A229941 3,  8, 24;
%e A229941 3,  9, 18;
%e A229941 3, 10, 15;
%e A229941 3, 12, 12;
%e A229941 4,  5, 20;
%e A229941 4,  6, 12;
%e A229941 4,  8,  8;
%e A229941 5,  5, 10;
%e A229941 6,  6,  6
%t A229941 {p, q, r} /. {ToRules[Reduce[0 < p <= q <= r && 1/p + 1/q + 1/r == 1/2, {p, q, r}, Integers] ]} // Flatten
%Y A229941 Cf. A230400, A260819.
%K A229941 easy,fini,nonn,full,tabf
%O A229941 1,1
%A A229941 _Jean-François Alcover_, Oct 04 2013