A230866 Number of integers m such that m + (sum of digits in base-5 representation of m) = 2n.
1, 1, 1, 2, 2, 1, 2, 2, 1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 1, 2, 2, 1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 1, 2, 2, 1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 1, 2, 2, 1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 1, 2, 2, 1, 2, 2, 2, 3, 3, 3, 3, 2, 2, 2, 1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 1, 2, 2, 1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 1, 2, 2, 1, 2, 2, 1, 2, 3
Offset: 0
Links
- Donovan Johnson, Table of n, a(n) for n = 0..10000