A231345 Triangle read by rows: T(n,k), n>=1, k>=1, in which column k lists the odd numbers interleaved with k-1 zeros but T(n,1) = -1 and the first element of column k is in row k(k+1)/2.
-1, -1, -1, 1, -1, 0, -1, 3, -1, 0, 1, -1, 5, 0, -1, 0, 0, -1, 7, 3, -1, 0, 0, 1, -1, 9, 0, 0, -1, 0, 5, 0, -1, 11, 0, 0, -1, 0, 0, 3, -1, 13, 7, 0, 1, -1, 0, 0, 0, 0, -1, 15, 0, 0, 0, -1, 0, 9, 5, 0, -1, 17, 0, 0, 0, -1, 0, 0, 0, 3, -1, 19, 11, 0, 0, 1
Offset: 1
Examples
Triangle begins: -1; -1; -1, 1; -1, 0; -1, 3; -1, 0, 1; -1, 5, 0; -1, 0, 0; -1, 7, 3; -1, 0, 0, 1; -1, 9, 0, 0; -1, 0, 5, 0; -1, 11, 0, 0; -1, 0, 0, 3; -1, 13, 7, 0, 1; -1, 0, 0, 0, 0; -1, 15, 0, 0, 0; -1, 0, 9, 5, 0; -1, 17, 0, 0, 0; -1, 0, 0, 0, 3; -1, 19, 11, 0, 0, 1; -1, 0, 0, 7, 0, 0; -1, 21, 0, 0, 0, 0; -1, 0, 13, 0, 0, 0; ... For n = 15 the divisors of 15 are 1, 3, 5, 15 hence the abundance of 15 is 1 + 3 + 5 + 15 - 2*15 = 1 + 3 + 5 - 15 = -6. On the other hand the 15th row of triangle is -1, 13, 7, 0, 1, hence the alternating row sum is -1 - 13 + 7 - 0 + 1 = -6, equalling the abundance of 15. If n is even then the alternating sum of the n-th row of triangle is simpler than the sum of divisors of n minus 2*n. Example: the sum of divisors of 24 minus 2*24 is 1 + 2 + 3 + 4 + 6 + 8 + 12 + 24 - 2*24 = 60 - 48 = 12, and the alternating sum of the 24th row of triangle is -1 - 0 + 13 - 0 + 0 - 0 = 12.
Links
- Eric Weisstein's World of Mathematics, Abundance
- Eric Weisstein's World of Mathematics, Quasiperfect Number
Crossrefs
Formula
T(n,1) = -1; T(n,k) = A196020(n,k), for k >= 2.
Comments